在SQL中找到两个合并列的平均值 [英] Find the average of two combined columns in sql
问题描述
我想找到两列的平均值.我要计算col1和col2的总数,然后找到平均值(它们在多少个不同的行中).
I want to find the avg of the total of two columns. I want to count the total of col1 and the total of col2 then find the average(how many different rows they are in).
我已经设法在此 sqlfiddle (另请参阅下文),这是最好的方法吗?最初我以为我需要使用avg函数,但无法使用此函数来解决这个问题.
I have managed to come up with a solution in the this sqlfiddle (also see below) is this the best way? I initially thought I would need to use the avg function but couldn't work it out using this.
CREATE TABLE test (
id INT NOT NULL AUTO_INCREMENT PRIMARY KEY,
uid INT,
col1 INT,
col2 INT
) DEFAULT CHARACTER SET utf8 ENGINE=InnoDB;
INSERT INTO test (id, uid, col1, col2) VALUES
(1,5,8,12),
(2,1,2,3),
(3,1,2,33),
(4,5,25,50),
(5,5,22,3);
(
SELECT ((sum(col1) + sum(col2))/count(*))
FROM test
WHERE uid=5
)
推荐答案
通过定义AVG(col1) = SUM(col1)/COUNT(*)
和AVG(col2) = SUM(col2)/COUNT(*)
,因此(SUM(col1)+SUM(col2))/COUNT(*)
= AVG(col1) + AVG(col2)
.
By definition, AVG(col1) = SUM(col1)/COUNT(*)
and AVG(col2) = SUM(col2)/COUNT(*)
, therefore (SUM(col1)+SUM(col2))/COUNT(*)
= AVG(col1) + AVG(col2)
.
此外,加法的可交换性使我们得到(SUM(col1)+SUM(col2))/COUNT(*) = SUM(col1+col2)/COUNT(*)
,从而得到AVG(col1+col2)
.
Also, the commutativity of addition gives us (SUM(col1)+SUM(col2))/COUNT(*) = SUM(col1+col2)/COUNT(*)
and hence AVG(col1+col2)
.
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