用户最近的活动-PHP MySql [英] User recent activities - PHP MySql

问题描述

这是我的问题:我有3个MySql表，分别代表:用户帖子的照片，用户帖子的视频，用户帖子的评论，并且我需要查看10个(20、30、40 ...)的最新活动.用户. 例如在照片表中可能由以下内容组成:

Here's my problem: I have 3 MySql tables representing: photos a user post, videos a user post, comments a user post and I need to view the 10 (20, 30, 40...) most recent activities by the user. For example in photos table may be composed by:

user_id | photo_id   | photo_path | photo_name | date_added
   5    |     18     |  /photos   | pht_18.png |  2009-02-12
   5    |     21     |  /photos   | pht_21.png |  2009-02-15
   5    |     29     |  /photos   | pht_29.png |  2009-03-30 

视频表

user_id | video_id   |  video_url       |   date_added
   5    |     36     |  youtube.com/... |   2009-01-09
   5    |     48     |  youtube.com/... |   2009-02-18
   5    |     90     |  youtube.com/... |   2009-03-19

评论表

user_id | comment_id |   comment     |  date_added
   5    |     6      |   hi!         |  2009-02-11
   5    |     11     |   great photo |  2009-02-13
   5    |     19     |   nice shot!  |  2009-03-28

如您所见，这3个表具有不同数量的属性，那么我该如何进行联合呢?在获取查询结果的同时，我该如何理解该表所属的表?

As you can see the 3 tables have different number of attributes, so how can I do the union? and while fetching the query result how can i understand to wich table it belongs to?

因此，在用户个人资料页面上，我想当然地显示出他最近由DATE DESC排序的活动:

So in the user profile page I'd like to show his recent activities of course ordered by DATE DESC this way:

2009-09-01: user posted a video
2009-11-02: user posted a comment
2009-12-02: user posted a photo
2009-13-02: user posted a comment
2009-15-02: user posted a photo
2009-18-02: user posted a video
2009-19-03: user posted a video
2009-28-03: user posted a comment
2009-30-03: user posted a photo

有人可以帮我吗?

推荐答案

MySQL UNION查询可以在这里工作:

A MySQL UNION query could work here:

(SELECT `user_id`, `date_added`, 'photo' AS `type` FROM `photos` WHERE `user_id` = uid) UNION
 (SELECT `user_id`, `date_added`, 'video' AS `type` FROM `videos` WHERE `user_id` = uid) UNION
 (SELECT `user_id`, `date_added`, 'comment' AS `type` FROM `comments` WHERE `user_id` = uid)
 ORDER BY `date_added` DESC;

然后您将得到一个类似这样的结果集

Then you'd wind up with a result set like

user_id | date_added | type
    5   | 2009-01-03 | photo
    5   | 2008-12-07 | video
    5   | 2008-11-19 | comment

，依此类推. (当然，您当然可以将user_id留在SELECT之外)

and so on. (actually you can leave user_id out of the SELECT if you want, of course)

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