如何创建全局配置文件? [英] How to create global configuration file?

问题描述

是否可以使用在类内部可见的全局变量来创建配置文件?与此类似:

Is there any possibility to create a configuration file with global variables that are visible inside the class? Something similar to this:

config.php:

config.php:

$config['host_address'] = 'localhost';
$config['username '] = 'root';
$config['password'] = 'root';
$config['name'] = 'data';

db.php:

include('config.php');
class DB
{
    private $_config = array($config['host_address'], $config['username'], $config['password'], $config['name']);
    ...

当前属性:

private $ _config = array();

我不想通过构造函数传输到我的Singleton数据库连接器:

I don't want to transmit through the constructor to my Singleton database connector:

DB::getInstance(array('localhost', 'root', 'root', 'data'));

推荐答案

您的问题是您试图在此处的类定义中使用表达式:

Your problem is that you are trying to use an expression in the class definition here:

class DB
{
    private $_config = array($config['host_address'], ...

从语法上讲这是不正确的(您只能使用恒定值)，而且我不希望它在此处定位预期的范围.相反，您应该做的是在构造函数中初始化此属性:

That is syntactically incorrect (you can only use constant values for that), and I wouldn't expect it to locate the intended scope there. What you should do instead is initialize this property in the construtor instead:

class DB
{
    private $_config;

    function __construct() {
        global $config;
        $this->_config = array($config['host_address'], $config['username'], $config['password'], $config['name']);
    }

甚至更懒惰，只需使用include('config.php');代替global $config别名即可.这样，您的配置脚本将在构造函数中将$ config提取为局部变量，这就是您所需要的.

Or even lazier, just use include('config.php'); in place of the global $config alias. That way your config script will extract $config as local variable within the constructor, which is all you need.

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