解析用的DiffGram复杂的SOAP响应 [英] Parsing Complex Soap Response with diffgram
本文介绍了解析用的DiffGram复杂的SOAP响应的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我不能够解析低于从.NET Web服务，我获得两个类型的反应之一是，我已经解析它anytype类型的格式，但现在我需要解析如下XML
SOAP响应 ＆LT;肥皂：信封的xmlns：SOAP =http://schemas.xmlsoap.org/soap/envelope/的xmlns：XSI =HTTP：//www.w3。组织/ 2001 / XML模式实例的xmlns：XSD =http://www.w3.org/2001/XMLSchema＆GT;
＆LT;肥皂：身体与GT;
＆LT; GetReminderResponse的xmlns =http://tempuri.org/＆GT;
＆LT; GetReminderResult＆GT;
＆LT; XS：模式ID =NewDataSet的xmlns =的xmlns：XS =http://www.w3.org/2001/XMLSchema中的xmlns：MSDATA =瓮：架构 - 微软COM：XML-MSDATA ＆GT;
＆LT; XS：元素的名称=NewDataSetMSDATA：IsDataSet =真MSDATA：UseCurrentLocale =真正的＆GT;
＆LT; XS：复杂类型＆GT;
＆LT; XS：选择的minOccurs =0的maxOccurs =无界＆GT;
＆LT; XS：元素的名称=表＆GT;
＆LT; XS：复杂类型＆GT;
＆LT; XS：序列＆GT;
＆LT; XS：元素的名称=RemMessage类型=XS：字符串的minOccurs =0/＆GT;
＆LT; XS：元素的名称=InvM_Id类型=XS：INT的minOccurs =0/＆GT;
＆LT; XS：元素的名称=的DocType类型=XS：INT的minOccurs =0/＆GT;
＆LT; XS：元素的名称=PrmR_TypeId类型=XS：INT的minOccurs =0/＆GT;
＆LT; XS：元素的名称=PrmR_Id类型=XS：INT的minOccurs =0/＆GT;
＆LT; / XS：序列＆GT;
＆LT; / XS：复杂类型＆GT;
＆LT; / XS：组件＆gt;
＆LT; / XS：选择＆GT;
＆LT; / XS：复杂类型＆GT;
＆LT; / XS：组件＆gt;
＆LT; / XS：架构＆GT;
＆LT; diffgr：的DiffGram的xmlns：MSDATA =瓮：架构 - 微软COM：XML-MSDATA的xmlns：diffgr =瓮：架构 - 微软COM：XML-的DiffGram-V1＆GT;
＆LT; NewDataSet的xmlns =＆GT;
＆LT;表diffgr：ID =表1MSDATA：rowOrder =0＆GT;
＆LT; RemMessage＆GT; Exeed贴现额度的发票上的日期为2015年4月5日为Andrea迪诺罗尼亚，从3 - Lokhandwala陈列室和LT; / RemMessage＆GT;
＆LT; InvM_Id＆GT; 78455＆LT; / InvM_Id＆GT;
＆所述;！DOCTYPE→3＆下; /的DocType＆GT;
＆所述; PrmR_TypeId→3＆下; / PrmR_TypeId＆GT;
＆LT; PrmR_Id＆GT; 2213＆LT; / PrmR_Id＆GT;
＆LT; /表＆gt;
＆所述;表diffgr：ID =表2MSDATA：rowOrder =1＆GT;
＆LT; RemMessage＆GT; Exeed贴现额度的发票上的日期为2015年4月5日为ADITI SHAH，从3 - Lokhandwala陈列室和LT; / RemMessage＆GT;
＆LT; InvM_Id＆GT; 78456＆LT; / InvM_Id＆GT;
＆所述;！DOCTYPE→3＆下; /的DocType＆GT;
＆所述; PrmR_TypeId→3＆下; / PrmR_TypeId＆GT;
＆LT; PrmR_Id＆GT; 2214＆LT; / PrmR_Id＆GT;
＆LT; /表＆gt;
＆LT; / NewDataSet＆GT;
＆LT; / diffgr：＆的DiffGram GT;
＆LT; / GetReminderResult＆GT;
＆LT; / GetReminderResponse＆GT;
＆LT; / SOAP：身体与GT;
＆LT; / SOAP：信封＆GT;
解决方案
有在你的肥皂响应wchich数据类型的架构是完全地我怪异。但我一直内置code忽略的xs：架构的一部分，并创建GetReminder对象的数组（从您的previous后采取类型：<一href=\"http://stackoverflow.com/questions/29297741/how-to-parse-diffgram-anytype-response-from-net-webservice\">How解析从.NET Web服务的DiffGram anytype来响应）。我认为，更好的办法将为该结构创建KVMSerializables但低于它的工作方式太伟大;）
的ArrayList＆LT; GetReminder＆GT; LST =新的ArrayList＆LT; GetReminder＆GT;（）;
如果（envelope.bodyIn的instanceof SoapObject＆放大器;＆安培;！envelope.bodyIn = NULL）{
SoapObject所以=（SoapObject）envelope.bodyIn;
如果（so.hasProperty（GetReminderResult））{
SoapObject SO1 =（SoapObject）so.getProperty（GetReminderResult）;
如果（so1.hasProperty（的DiffGram））{
SoapObject soDiffg =（SoapObject）so1.getProperty（的DiffGram）;
如果（soDiffg.hasProperty（NewDataSet））{
SoapObject soNDSet =（SoapObject）soDiffg.getProperty（NewDataSet）; 的for（int i = 0; I＆LT; soNDSet.getPropertyCount（）;我++）{
SoapObject SOREM =（SoapObject）soNDSet.getProperty（ⅰ）;
GetReminder提醒=新GetReminder（）; 如果（soRem.hasProperty（RemMessage））{
reminder.setRemMessage（soRem.getPropertyAsString（RemMessage））;
}
如果（soRem.hasProperty（InvM_Id））{
reminder.setInvM_Id（Integer.valueOf（soRem.getPropertyAsString（InvM_Id）））;
}
如果（soRem.hasProperty（的DocType））{
reminder.setDocType（Integer.valueOf（soRem.getPropertyAsString（的DocType）））;
}
如果（soRem.hasProperty（PrmR_TypeId））{
reminder.setPrmR_TypeId（Integer.valueOf（soRem.getPropertyAsString（PrmR_TypeId）））;
}
如果（soRem.hasProperty（PrmR_Id））{
reminder.setPrmR_Id（Integer.valueOf（soRem.getPropertyAsString（PrmR_Id）））;
} lst.add（提示）;
}
}
}
}
} 的System.out.println（lst.size（））;
问候，马尔辛 -
I am not able to parse below soap response from a .net webservice,i am getting two type of response one is of anytype format which i have parsed it,but now i need to parse the below xml
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<GetReminderResponse xmlns="http://tempuri.org/">
<GetReminderResult>
<xs:schema id="NewDataSet" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
<xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
<xs:complexType>
<xs:choice minOccurs="0" maxOccurs="unbounded">
<xs:element name="Table">
<xs:complexType>
<xs:sequence>
<xs:element name="RemMessage" type="xs:string" minOccurs="0"/>
<xs:element name="InvM_Id" type="xs:int" minOccurs="0"/>
<xs:element name="DocType" type="xs:int" minOccurs="0"/>
<xs:element name="PrmR_TypeId" type="xs:int" minOccurs="0"/>
<xs:element name="PrmR_Id" type="xs:int" minOccurs="0"/>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:choice>
</xs:complexType>
</xs:element>
</xs:schema>
<diffgr:diffgram xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1">
<NewDataSet xmlns="">
<Table diffgr:id="Table1" msdata:rowOrder="0">
<RemMessage>Exeed Discount Limit on Invoice dated on 04/05/2015 for ANDREA NORONHA , from 3 - Lokhandwala Showroom</RemMessage>
<InvM_Id>78455</InvM_Id>
<DocType>3</DocType>
<PrmR_TypeId>3</PrmR_TypeId>
<PrmR_Id>2213</PrmR_Id>
</Table>
<Table diffgr:id="Table2" msdata:rowOrder="1">
<RemMessage>Exeed Discount Limit on Invoice dated on 04/05/2015 for ADITI SHAH , from 3 - Lokhandwala Showroom</RemMessage>
<InvM_Id>78456</InvM_Id>
<DocType>3</DocType>
<PrmR_TypeId>3</PrmR_TypeId>
<PrmR_Id>2214</PrmR_Id>
</Table>
</NewDataSet>
</diffgr:diffgram>
</GetReminderResult>
</GetReminderResponse>
</soap:Body>
</soap:Envelope>
解决方案
there is schema of data types in Your Soap-response wchich is completly weird for me. But i've built code that ignores xs:schema part and creates array of GetReminder objects (type taken from Your previous post: How to parse diffgram anytype response from .net webservice). I think, that better idea would be creating KVMSerializables for the structure but the way below it works great too ;)
ArrayList<GetReminder> lst = new ArrayList<GetReminder>();
if(envelope.bodyIn instanceof SoapObject && envelope.bodyIn!=null){
SoapObject so=(SoapObject)envelope.bodyIn;
if(so.hasProperty("GetReminderResult")){
SoapObject so1 = (SoapObject) so.getProperty("GetReminderResult");
if(so1.hasProperty("diffgram")){
SoapObject soDiffg = (SoapObject) so1.getProperty("diffgram");
if(soDiffg.hasProperty("NewDataSet")){
SoapObject soNDSet = (SoapObject) soDiffg.getProperty("NewDataSet");
for (int i = 0; i < soNDSet.getPropertyCount(); i++) {
SoapObject soRem = (SoapObject) soNDSet.getProperty(i);
GetReminder reminder = new GetReminder();
if (soRem.hasProperty("RemMessage")) {
reminder.setRemMessage(soRem.getPropertyAsString("RemMessage"));
}
if (soRem.hasProperty("InvM_Id")) {
reminder.setInvM_Id(Integer.valueOf(soRem.getPropertyAsString("InvM_Id")));
}
if (soRem.hasProperty("DocType")) {
reminder.setDocType(Integer.valueOf(soRem.getPropertyAsString("DocType")));
}
if (soRem.hasProperty("PrmR_TypeId")) {
reminder.setPrmR_TypeId(Integer.valueOf(soRem.getPropertyAsString("PrmR_TypeId")));
}
if (soRem.hasProperty("PrmR_Id")) {
reminder.setPrmR_Id(Integer.valueOf(soRem.getPropertyAsString("PrmR_Id")));
}
lst.add(reminder);
}
}
}
}
}
System.out.println(lst.size());
Regards, Marcin
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