回声检查选中了哪个复选框 [英] Echo check on which checkbox was checked

问题描述

我有一个可以编辑内容的表格，这时，我将复选框的值回显到输入字段中，但是我宁愿保留原始复选框并显示选中了哪个复选框.

I have a form where i can edit the content, at this point i'm echo'ing the value of a checkbox into an input field but i rather keep the original checkbox's and show which one was checked.

     <div class="col-sm-9">
        <label class="checkbox-inline">
            <input type="radio" class="px" name="radiochoice" id="radio11" class="radio" value="No Charge" />
            <span class="lbl">No Charge</span>
        </label>
        <br>
    </div>



    <div class="col-sm-9">
        <label class="checkbox-inline">
            <input type="radio" class="px" name="radiochoice" id="radio7" class="radio" value="185.00"  />
            <span class="lbl">Networking: $185.00</span>
        </label>
        <br>
    </div>

    <div class="col-sm-9">
        <label class="checkbox-inline">
            <input type="radio" class="px" name="radiochoice" id="radio8" class="radio" value="125.00"/>
            <span class="lbl">Mechanical: $125.00</span>
        </label>
        <br>
    </div>

如果我回显该值，它将仅显示该值，那么如何显示已选中哪个复选框呢?

If i echo the value its just going to show the value, how do i show which checkbox was checked instead?

value=<?php echo $radiochoice;?>>

目标:

if ($radiochoice == "No Charge") {          
echo '<div class="col-sm-9">';
echo '<label class="checkbox-inline">';    
echo '<input type="radio" class="px" name="radiochoice" id="radio11" class="radio" value="No Charge" checked/>';
echo '<span class="lbl">No Charge</span>';
echo '</label>';
echo '<br>';
echo '</div>';

echo '<div class="col-sm-9">';
echo '<label class="checkbox-inline">';
echo '<input type="radio" class="px" name="radiochoice" id="radio7" class="radio" value="185.00"  />';
echo '<span class="lbl">Networking: $185.00</span>';
echo '</label>';
echo '<br>';
echo '</div>';

echo '<div class="col-sm-9">';
echo '<label class="checkbox-inline">';
echo '<input type="radio" class="px" name="radiochoice" id="radio8" class="radio" value="125.00"   />';
echo '<span class="lbl">Mechanical: $125.00</span>';
echo '</label>';
echo '<br>';
echo '</div>';

echo '<div class="col-sm-9">';
echo '<label class="checkbox-inline">';
echo '<input type="radio" class="px" name="radiochoice" id="radio9" class="radio" value="59.00" />';
echo '<span class="lbl">Remote half: $59.00</span>';
echo '</label>';
echo '<br>';
echo '</div>';

echo '<div class="col-sm-9">';
echo '<label class="checkbox-inline">';
echo '<input type="radio" class="px" name="radiochoice" id="radio10" class="radio" value="89.00"   />';
echo '<span class="lbl">Remote 1 HR: $89.00</span>';
echo '</label>';
echo '<br>';
echo '</div>';


} elseif ($answer == 185.00) {

ETC ETC ETC

ETC ETC ETC

推荐答案

，但您每次添加的输入内容都不美观

while not elegant on every input you can add

<input type="radio" class="px" name="radiochoice" id="radio7" class="radio" value="185.00"  <?php if($_POST['radiochoice'] =='185.00'){echo "checked='checked'";} ?>/>

相应地更改值，它可能是$ _GET，具体取决于表单操作

alter the value accordingly, and it may be $_GET, depending on form action

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