如何在Android中得到开关值？ [英] How to get switch value in Android?

问题描述

我已经把在主要活动开关部件，我也有一个扩展的BroadcastReceiver第二次活动。我想在第二个活动开关部件的布尔状态。

I have placed a switch widget in Main Activity, I also have a second activity that extends BroadcastReceiver. I want to get the boolean state of switch widget in second activity.

如果我键入

Switch s = (Switch) findViewById(R.id.switch1);

它说findViewById是未定义的类型SecondActivity。问题是Android不容许我得到扩展广播接收器一类开关的值。

it says findViewById is undefined for the type SecondActivity. The problem is Android doesn't allow me to get the value of switch in a class that extends Broadcast Receiver.

我想知道开关，即的状态，​​开关是否开启或关闭，但在第二个活动。我怎样才能实现呢？

I want to know the state of switch, i.e, whether switch is on or off, but in second activity. How can I achieve it?

推荐答案

调用 findViewById（）从活动只能访问是，布局的一部分意见活动。你不能用它来搜索其他任何活动的布局。

Calling findViewById() from an Activity can only access Views that are a part of the layout of that Activity. You cannot use it to search the layout of any other Activity.

根据您的应用程序的设计，您可以使用其中的一个：

Depending on your app design, you can use one of these:

1），通过发送切换到SecondActivity的值的额外意图

的在活动：的

Intent mIntent = new Intent(this, SecondActivity.class);
mIntent.putExtra("switch", s.isChecked());
startActivity(mIntent);

的在SecondActivity：的

boolean isChecked = getIntent().getBooleanExtra("switch", false);

2）的值保存到变化的preference，并在SecondActivity阅读preferences

的在活动：的

SharedPreferences settings = PreferenceManager.getDefaultSharedPreferences(this);
SharedPreferences.Editor e = settings.edit();
e.putBoolean("switch", s.isChecked());
e.commit();

的在SecondActivity：的

SharedPreferences settings = PreferenceManager.getDefaultSharedPreferences(this);
boolean isChecked = settings.getBoolean("switch", false);

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