使用SUM()的MYSQL选择查询 [英] MYSQL Select Query with SUM()

问题描述

我有下表:

| campaign_id | source_id | clicked | viewed |
----------------------------------------------
| abc         | xxx       | 0       | 0      |  
| abc         | xxx       | 1       | 0      |
| abc         | xxx       | 1       | 1      | 
| abc         | yyy       | 0       | 0      |    
| abc         | yyy       | 1       | 0      |    
| abc         | yyy       | 1       | 1      |    
| abc         | yyy       | 0       | 0      |

我需要以下输出:

xxx > Total: 3 // Clicked: 2 // Viewed 1
yyy > Total: 4 // Clicked: 2 // Viewed 1

我知道我必须在查询中使用某种SUM()，但我不知道如何在source_id中的多个唯一值之间进行区分(例如foreach，idk).

I know that I have to use some sort of SUM() in my query, but I don't know how to differ between those multiple unique values in the source_id (something like foreach, idk).

如何仅通过一个查询就可以显示所有唯一source_ids的统计信息?

How can I get such an output which shows stats from all unique source_ids by using only one query?

推荐答案

尝试一下:

SELECT source_id, (SUM(clicked)+SUM(viewed)) AS Total
FROM your_table
GROUP BY source_id

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