SQL:如何每天选择一条记录,假设每天包含多于1个值的MySQL [英] SQL: How to select one record per day, assuming that each day contain more than 1 value MySQL
问题描述
我想从'2013-04-01 00:00:00'
到'today'
中选择记录,但是每天都有很多价值,因为它们每15分钟保存一个值,所以我只希望每天有第一个或最后一个值.
I want to select records from '2013-04-01 00:00:00'
to 'today'
but, each day has lot of value, because they are saving each 15 minutes a value, so I want only the first or last value from each day.
表架构:
CREATE TABLE IF NOT EXISTS `value_magnitudes` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`value` float DEFAULT NULL,
`magnitude_id` int(11) DEFAULT NULL,
`sdi_belongs_id` varchar(255) COLLATE utf8_unicode_ci DEFAULT NULL,
`reading_date` datetime DEFAULT NULL,
`created_at` datetime DEFAULT NULL,
`updated_at` datetime DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=1118402 ;
错误的SQL:
SELECT value FROM `value_magnitudes` WHERE `value_magnitudes`.`reading_date` BETWEEN '2013-04-01 00:00:00' AND '2013-04-02 00:00:00' AND (`value_magnitudes`.magnitude_id = 234) LIMIT 1
SELECT value FROM `value_magnitudes` WHERE `value_magnitudes`.`reading_date` BETWEEN '2013-04-02 00:00:00' AND '2013-04-03 00:00:00' AND (`value_magnitudes`.magnitude_id = 234) LIMIT 1
SELECT value FROM `value_magnitudes` WHERE `value_magnitudes`.`reading_date` BETWEEN '2013-04-03 00:00:00' AND '2013-04-04 00:00:00' AND (`value_magnitudes`.magnitude_id = 234) LIMIT 1
SELECT value FROM `value_magnitudes` WHERE `value_magnitudes`.`reading_date` BETWEEN '2013-04-04 00:00:00' AND '2013-04-05 00:00:00' AND (`value_magnitudes`.magnitude_id = 234) LIMIT 1
SELECT value FROM `value_magnitudes` WHERE `value_magnitudes`.`reading_date` BETWEEN '2013-04-05 00:00:00' AND '2013-04-06 00:00:00' AND (`value_magnitudes`.magnitude_id = 234) LIMIT 1
etc ...
如果可能的话,我希望一劳永逸...
I want all in one if possible...
非常感谢您.
我的意思是,我每天都有一个查询,但是我只想从reading_date >= '2013-04-01 00:00:00'
c
I mean, I have a query per day, but I just want to make a single query from reading_date >= '2013-04-01 00:00:00'
c
我在table.value_magnitudes
中有 64,260 条记录,执行并响应该查询需要很长时间,有时甚至超时.
I have 64,260 records in that table.value_magnitudes
and it takes sooooooooo long to excecute and response that query, and sometimes timeout conection.
推荐答案
要获取每个日期的第一条记录
To get the first entry for every date you can do
select * from value_magnitudes
where id in
(
SELECT min(id)
FROM value_magnitudes
WHERE magnitude_id = 234
and date(reading_date) >= '2013-04-01'
group by date(reading_date)
)
这篇关于SQL:如何每天选择一条记录,假设每天包含多于1个值的MySQL的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!