将某些值排序到顶部 [英] Sort certain values to the top

问题描述

我有一个包含以下数据(简化)的MySQL表:

I have a MySQL table with the following data (simplified):

INSERT INTO `stores` (`storeId`, `name`, `country`) VALUES
(1, 'Foo', 'us'),
(2, 'Bar', 'jp'),
(3, 'Baz', 'us'),
(4, 'Foo2', 'se'),
(5, 'Baz2', 'jp'),
(6, 'Bar3', 'jp');

现在，我希望能够获得以客户所在国家/地区开头的分页商店列表.

Now, I want to be able to get a paginated list of stores that begins with the customers country.

例如，一个美国客户将看到以下列表:

For example, an american customer would see the following list:

Foo
Baz
Bar
Foo2
Baz2
Bar3

我现在正在使用的天真的解决方案(例如，有一个美国客户，页面大小为3):

The naive solution I'm using right now (example with an american customer and page size 3):

(SELECT * FROM stores WHERE country = "us") UNION (SELECT * FROM stores WHERE country != "us") LIMIT 0,3

有没有更好的方法可以做到这一点?可以使用ORDER BY并让其将某个值放在顶部吗?

Are there any better ways of doing this? Could ORDER BY be used and told to put a certain value at the top?

推荐答案

尝试一下:

SELECT * FROM stores ORDER BY country = "us" DESC,  storeId

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