从Android应用程序将数据插入MySQL数据库.更改未反映在数据库中 [英] Insert data into MySQL database from Android app. Changes not reflected in database

问题描述

我正在编写一个将数据插入MySQL数据库的应用程序.我用PHP编写了sql查询，当我在android应用程序中输入值时，在log cat中没有看到任何错误，但是这些值未存储在数据库中.

I'm writing an application to insert data into a MySQL database. I wrote the sql query in PHP and when I enter values in the android application, I don't seen any errors in the log cat but the values aren't getting stored in the database.

这是PHP代码:

<?php

$connect = mysqli_connect("localhost","root","","easyassigndroid");

if(mysqli_connect_errno($connect))
{
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
else
{
    echo "success";
}

$username = isset($_POST['sPhone']) ? $_POST['sPhone'] : '';
$password = isset($_POST['sPassword']) ? $_POST['sPassword'] : '';

$query = mysqli_query($connect, "insert into users (sphone, spassword) values ('$username' ,'$password') ");

mysqli_close($connect);
?>

这是android部分:

Here's the android part:

protected void onCreate(Bundle savedInstanceState) {

    // TODO Auto-generated method stub
    super.onCreate(savedInstanceState);

    setContentView(R.layout.register_lecturer);

    phonenum = (EditText) findViewById(R.id.id_phone);
    password = (EditText) findViewById(R.id.id_password);

    sPhone = phonenum.toString();
    sPassword = password.toString();

    registerLecturer=(Button)findViewById(R.id.lecturerregister);
    registerLecturer.setOnClickListener(new View.OnClickListener() {

        public void onClick(View v) {
            // TODO Auto-generated method stub

            httpclient = new DefaultHttpClient();
            httppost = new HttpPost("http://10.0.2.2/project/insert.php");

            try
            {
                nameValuePairs = new ArrayList<NameValuePair>();
                nameValuePairs.add(new BasicNameValuePair("sphone", sPhone));
                nameValuePairs.add(new BasicNameValuePair("spassword", sPassword));

                httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
                response = httpclient.execute(httppost);
            }
            catch(Exception e)
            {
                e.printStackTrace();
            }
        }
    });


}

我是Android和PHP编码的初学者.谁能告诉我问题出在我的代码中吗?我的项目工作需要这个.

I'm a beginner to both Android and PHP coding. Can anyone tell me where the problem is in my code? I need this for my project work.

推荐答案

只有一点:我们使用

x.getText().toString(); 

其中x是EditText对象，对吗?希望对您有帮助.

where x is an EditText object, right? hope it helps at all.

但是，由于这是在onCreate()中完成的，而不是在onClick()中完成的，因此您应该进行以下更改:

But, since this is being done in the onCreate() - rather than inside the onClick() - you should change:

nameValuePairs.add(new BasicNameValuePair("sphone", sPhone));

到

nameValuePairs.add(new BasicNameValuePair("sphone", phonenum.getText().toString()));

对于另一个也是类似的. 干杯.

And similarly for the other one. Cheers.

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