在mysql中比较两个逗号分隔的值并获取匹配的计数 [英] compare two comma separated values in mysql and get the matched count
问题描述
比较mysql中逗号分隔的值,并在countcolumn中获取匹配的输出
Compare comma separated values in mysql and get the matched output in countcolumn
示例:
id values
1 1,2,3
2 3
3 1,3
通过比较ID 1和2,输出应为1
By comparing id 1 and 2 the output should be 1
通过比较ID 2和3,输出应为1
By comparing id 2 and 3 the output should be 1
通过比较ID 3和1,输出应为2
By comparing id 3 and 1 the output should be 2
推荐答案
首先,您列出的数据实际上应该以一种格式存储,数据库的每一行都存储一个id
和一个value
,即3元素列表将对应3行.如果对您的结构进行了更改,则以下答案将是相关的比较两个结果之间的相似性设置
Firstly, the data you listed should really be stored in a format where each row of the database stores a single id
and a single value
, i.e. the 3-element list would correspond to 3 rows. If that change was made to your structure then the following answer would be relevant Compare similarities between two result sets
尽管如此,这是我整理的一个不错的MySQL小功能,您可以将其用于您的目的.这将接受2个参数,这些参数是逗号分隔的列表,并将返回出现在列表2中的列表1中的元素数.
As it stands though, here's a nice little MySQL function I put together that you could use for your purposes. This takes in 2 arguments which are comma-separated lists and will return the number of elements in list 1 that appear in list 2.
这并不能阻止列表1中的重复ID在列表2中被计算两次(即"1,1,2"和"1,2"将返回值3),但是您可以弄清楚如何如果您愿意的话,可以很容易地对其进行调整.
This will not as it stands prevent duplicate IDs in list 1 being counted twice in list 2 (i.e. '1,1,2' and '1,2' would return a value of 3) but you could figure out how to adjust this fairly easily to do that if you so wished.
要使用此功能,只需执行
To use this, just do
SELECT
countMatchingElements( '3' , '1,3' ) AS testCase1
countMatchingElements( '1,2,3' , '1,3' ) AS testCase2
countMatchingElements( '3' , '1,2,3' ) AS testCase3;
存储的功能逻辑如下
CREATE DEFINER = `yourUserGoesHere`@`%` FUNCTION `countMatchingElements`(inFirstList VARCHAR(1000), inSecondList VARCHAR(1000))
RETURNS tinyint(3) unsigned
NO SQL
DETERMINISTIC
SQL SECURITY INVOKER
BEGIN
DECLARE numReturn TINYINT UNSIGNED DEFAULT 0;
DECLARE idsInFirstList TINYINT UNSIGNED;
DECLARE currentListItem VARCHAR(255) DEFAULT '';
DECLARE currentID TINYINT UNSIGNED;
SET idsInFirstList = ( CHAR_LENGTH( inFirstList ) + 1 ) - CHAR_LENGTH( REPLACE( inFirstList , ',' , '' ) );
SET currentID = 1;
-- Loop over inFirstList, and for each element that is in inSecondList increment numReturn
firstListLoop: REPEAT
SET currentListItem = SUBSTRING_INDEX( SUBSTRING_INDEX( inFirstList , ',' , currentID ) , ',' , -1 );
IF FIND_IN_SET( currentListItem , inSecondList ) THEN
SET numReturn = numReturn + 1;
END IF;
SET currentID = currentID + 1;
UNTIL currentID > idsInFirstList
END REPEAT firstListLoop;
RETURN numReturn;
END
这篇关于在mysql中比较两个逗号分隔的值并获取匹配的计数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!