在SQL中使用PHP将日期转换为DATETIME [英] Converting dates with PHP for DATETIME in SQL

问题描述

我有一个PHP论坛，其日期格式如下 dd/mm/yyyy hh:mm:ss.但是，我需要以yyyy-mm-dd hh:mm:ss的格式将它作为SQL的DATETIME插入.如何转换这些数据?

I have a forum in PHP which takes a date like in the form dd/mm/yyyy hh:mm:ss. However, I need to insert it for SQL as a DATETIME in the format as yyyy-mm-dd hh:mm:ss. How can I convert this data?

推荐答案

您的日期时间格式错误:dd/mm/yyyy hh:mm:ss.也许您是说d/m/Y H:i:s

Your date time format is wrong: dd/mm/yyyy hh:mm:ss. Probably you mean d/m/Y H:i:s

如果您使用的是5.3+版本，则可以使用安全的方法将日期时间转换为另一种格式.这是一个示例:

If you have 5.3+ version there is safe way to convert the date time into another format. Here's an example:

$timestamp = '31/05/2001 12:22:56';
$timestamp = DateTime::createFromFormat('d/m/Y H:i:s', $timestamp);
echo $timestamp->format('Y-m-d H:i:s');

或者，如果您喜欢更多的程序方式:

or if you like more procedural way:

$timestamp = '31/05/2001 12:22:56';
$timestamp = date_create_from_format('d/m/Y H:i:s', $timestamp);
echo date_format($timestamp, 'Y-m-d H:i:s');

请谨慎对待先前的建议.有些完全错误，另一些可能导致错误.

Be careful with previous suggestions. Some are completely wrong and others could lead to errors.

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