mysqli bind_param()致命错误 [英] mysqli bind_param() fatal error

问题描述

我的代码有错误，有人可以帮助我吗?

I Have an Error at my Code could someone help me?

<?php
  $db = new mysqli("localhost","root","","karmintalender");

  $owner_ID = 1;

  $sql = "SELECT name, kalender_ID FROM kalender WHERE ersteller_ID = ?";
  $stmt = $db->prepare($sql);
  $stmt->bind_param("i", $owner_ID);
  $stmt->execute();
  $stmt->bind_results($name, $kalender_ID);

  while ($stmt->fetch()) {
    echo $name . " " . $kalender_ID;
  }
?>

当我打开它时，出现此错误致命错误:在第8行的G:\ xampp \ htdocs \ Karmintalender \ test.php中的非对象上调用成员函数bind_param()"

When I open it this error appears "Fatal error: Call to a member function bind_param() on a non-object in G:\xampp\htdocs\Karmintalender\test.php on line 8"

推荐答案

此行上的一个字段不存在，请检查它们.

One of your fields on this line doesn't exist,check them.

$sql = "SELECT name, kalender_ID FROM kalender WHERE ersteller_ID = ?";

此外，您应该检查$ stmt.

Also, you should be checking for $stmt.

$db = new mysqli("localhost","root","","karmintalender");

 $owner_ID = 1;

 $sql = "SELECT name, kalender_ID FROM kalender WHERE ersteller_ID = ?";
 $stmt = $db->prepare($sql);
 if($stmt){
     $stmt->bind_param("i", $owner_ID);
     $stmt->execute();
     $stmt->bind_results($name, $kalender_ID);

     while ($stmt->fetch()) {
       echo $name . " " . $kalender_ID;
     }
 }

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