PHP MySQLi仅以JSON返回一行 [英] PHP MySQLi is just returning one row in JSON

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本文介绍了PHP MySQLi仅以JSON返回一行的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在处理以下代码.为什么我的JSON输出中只有一行?

I am working on the below code. Why am I getting only one row in my JSON output?

$items = [];
if ($stmt = $this->conn->prepare("SELECT * FROM $tbl")) {
    $stmt->execute();
    $result = $stmt->get_result();
    if ($result->num_rows > 0) {
    while ($row = $result->fetch_assoc()) {
         $items = $row;
     }
    $stmt->free_result();
    $stmt->close();
    }
    $this->conn->close();
}
echo json_encode($items);

推荐答案

之所以会发生这种情况,是因为您要遍历所有行并将每个行分配给$items:

This happens because you are going through the rows and assigning each of them to $items:

while ($row = $result->fetch_assoc()) {
    $items = $row;
}

因此,在循环结束后,您将得到一个变量,该变量是在该循环的最后一次迭代期间分配的$ row.

So after the loop is finished you end up with a variable which is a $row that was assigned during the last iteration of that loop.

您需要将值推入数组,如下所示:

You would need to push the values to an array like so:

$items[] = $row;

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