为什么会发生此PHP错误:“严格的标准:mysqli :: next_result():没有下一个结果集."? [英] Why this PHP error occurs: "Strict standards: mysqli::next_result(): There is no next result set."?

问题描述

我有代码，基本上是 php.net 的代码，但是由于某些原因它不起作用.这是php.net上的代码:

I have code, which is basically a copy of a php.net's code, but for some reason it does not work. Here is the code on php.net:

<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");

/* check connection */
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

$query  = "SELECT CURRENT_USER();";
$query .= "SELECT Name FROM City ORDER BY ID LIMIT 20, 5";

/* execute multi query */
if ($mysqli->multi_query($query)) {
    do {
        /* store first result set */
        if ($result = $mysqli->store_result()) {
            while ($row = $result->fetch_row()) {
                printf("%s\n", $row[0]);
            }
            $result->free();
        }
        /* print divider */
        if ($mysqli->more_results()) {
            printf("-----------------\n");
        }
    } while ($mysqli->next_result());
}

/* close connection */
$mysqli->close();
?>

我进行的第一个更改是连接:

$mysqli = new mysqli("localhost", "root", "", "fanfiction");

我所做的第二个更改是查询:

$query = "SELECT first FROM tests;";
$query .= "SELECT second FROM tests;";
$query .= "SELECT third FROM tests;";
$query .= "SELECT fourth FROM tests";

完整的代码，其中包含我的更改

<?php
$mysqli = new mysqli("localhost", "root", "", "fanfiction");

/* check connection */
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

$query = "SELECT first FROM tests;";
$query .= "SELECT second FROM tests;";
$query .= "SELECT third FROM tests;";
$query .= "SELECT fourth FROM tests";

/* execute multi query */
if ($mysqli->multi_query($query)) {
    do {
        /* store first result set */
        if ($result = $mysqli->store_result()) {
            while ($row = $result->fetch_row()) {
                printf("%s\n", $row[0]);
            }
            $result->free();
        }
        /* print divider */
        if ($mysqli->more_results()) {
            printf("-----------------\n");
        }
    } while ($mysqli->next_result());
}

/* close connection */
$mysqli->close();
?>

我得到的错误:

严格的标准: mysqli :: next_result():没有下一个结果集. 请调用 mysqli_more_results()/ mysqli :: more_results()进行检查 是否调用此函数/方法 行号

Strict standards: mysqli::next_result(): There is no next result set. Please, call mysqli_more_results()/mysqli::more_results() to check whether to call this function/method in address on line line number

我在网上搜索了一个解决方案，特别是在StackOverflow上，但是没有找到有用的解决方案.我发现的大多数解决方案都是这两种解决方案之一:

I searched a solution over the net, and particularly here on StackOverflow, but I did not find helpful solutions. Most of the solutions I found were one of those two:

• 在此解决方案中， @Hammerite 表示将循环从do-while更改为while.这表明php.net的代码逻辑上有问题，我很难相信.但更重要的是，它对我不起作用.
• 在此解决方案中， @mickmackusa 建议在while中添加一个条件并将$mysqli->next_result()更改为$mysqli->next_result() && $mysqli->more_results()，但是这种解决方案效果不佳.它确实消除了错误，但忽略了最后的结果.

• In this solution,@Hammerite says to change the loop from do-while to while. This suggest that php.net's code has a problem in its logic, and I find it very hard to believe. But more importantly, it just does not work for me.
• In this solution, @mickmackusa suggests to add a condition in the while and change $mysqli->next_result() to $mysqli->next_result() && $mysqli->more_results(), but this solution do not work quite well. It does indeed removes the error but it omits the last result.

推荐答案

尝试使用

} while ($mysqli->more_results() && $mysqli->next_result());

sscce :

<?php
ini_set('display_errors', 'on');
error_reporting(E_ALL|E_STRICT);

$mysqli = new mysqli("localhost", "localonly", "localonly", "test");
/* check connection */
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

$mysqli->query('CREATE TEMPORARY TABLE City (ID int auto_increment, `Name` varchar(32), primary key(ID))') or die($mysqli->error);

$stmt = $mysqli->prepare("INSERT INTO City (`Name`) VALUES (?)") or die($mysqli->error);
$stmt->bind_param('s', $city) or die($stmt->error);
foreach(range('A','Z') as $c) {
    $city = 'city'.$c;
    $stmt->execute() or die($stmt->error);
}

$query  = "SELECT CURRENT_USER();";
$query .= "SELECT Name FROM City ORDER BY ID LIMIT 20, 5";

/* execute multi query */
if (!$mysqli->multi_query($query)) {
    trigger_error('multi_query failed: '.$mysqli->error, E_USER_ERROR);
}
else {
    do {
        /* store first result set */
        if ($result = $mysqli->store_result()) {
            while ($row = $result->fetch_row()) {
                printf("'%s'\n", $row[0]);
            }
            $result->free();
        }
        /* print divider */
        if ($mysqli->more_results()) {
            printf("-----------------\n");
        }
    } while ($mysqli->more_results() && $mysqli->next_result());
}

打印

'localonly@localhost'
-----------------
'cityU'
'cityV'
'cityW'
'cityX'
'cityY'

没有警告/通知.

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