显示数据库中的所有表 [英] Displaying all tables in a database

问题描述

如何使用PHP显示数据库中的所有信息(所有表和记录)?我读过将表格显示为HTML表格，但是如何对所有表格进行显示呢?

How do I display out all the information in a database (All tables and records) using PHP? I read displaying tables as HTML table but how do I do it for all the tables?

我在这里尝试了该示例: http://davidwalsh.name/html-mysql-php

I tried the example here: http://davidwalsh.name/html-mysql-php

但是它显示了表名，如何显示所有值?

But it shows the table names, how do I also display all the values?

推荐答案

如果要在mysql中使用values提取所有tables，则可以使用以下代码:

If you want to pull all tables with the values in mysql, you can use the following code:

<?php
    mysql_connect ("localhost", "DB_USER", "DB_PASSWORD"); //your mysql connection  
    mysql_select_db('DB_NAME') or die( "Unable to select database"); //your db name 

    $tables = mysql_query("SELECT table_name FROM information_schema.tables WHERE table_schema='DB_NAME'"); //pull tables from theh databsase
    while ($table= mysql_fetch_row($tables)) { 
        $rsFields = mysql_query("SHOW COLUMNS FROM ".$table[0]); 
        while ($field = mysql_fetch_assoc($rsFields)) { 
            echo $table[0].".".$field["Field"].", "; //prints out all columns 
        } 
        echo $table[0];
        $query = "SELECT * FROM ".$table[0]; //prints out tables name
        $result = mysql_query($query); 
        PullValues($result); //call function to get all values
    }  


    //function to pull all values from tables
    function PullValues($result) 
    {     
        if($result == 0) 
        { 
            echo "<b>Error ".mysql_errno().": ".mysql_error()."</b>"; 
        } 
        elseif (@mysql_num_rows($result) == 0) 
        { 
            echo("<b>Query completed. No results returned.</b><br>"); 
        } 
        else 
        { 
            echo "<table border='1'> 
                <thead> 
                <tr><th>[Num]</th>"; 
            for($i = 0;$i < mysql_num_fields($result);$i++) 
            { 
                echo "<th>" . $i . "&nbsp;-&nbsp;" . mysql_field_name($result, $i) . "</th>"; 
            } 
            echo "  </tr> 
                </thead> 
                <tbody>"; 
            for ($i = 0; $i < mysql_num_rows($result); $i++) 
            { 
                echo "<tr><td>[$i]</td>"; 
                $row = mysql_fetch_row($result); 
                for($j = 0;$j < mysql_num_fields($result);$j++)  
                { 
                    echo("<td>" . $row[$j] . "</td>"); 
                } 
                echo "</tr>"; 
            } 
            echo "</tbody> 
            </table>"; 
        }  //end else 
    }  
?>

我正在使用它，并且在mysql中可以正常工作，对于mysqli，您需要进行一些微调.

I am using this and works fine in mysql, for mysqli you need to tweak it a very little.

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