Android的使用名字来取得联络号码 [英] Android get contact number using name

问题描述

我想在Android，是以联系人姓名作为一个字符串输入，并返回他的电话号码，如果该联系人在电话簿中存在的应用程序...

I am trying to make an application on android that takes the contact name as a string input and returns his phone number if that contact exists in the phone book...

我试过各地寻找，但没有明确的教程就如何做到这些。

I tried searching around but there is no clear tutorial as to how to do exactly that

输入：联系人姓名
输出：电话号码

input:contact name outputs:the phone number

请帮忙

      Cursor cursor = context.getContentResolver().query(ContactsContract.Contacts.CONTENT_URI,null, null, null, null); 


     while (cursor.moveToNext()) { 
         String name = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));

         if(name.equalsIgnoreCase(token3)) {

        try{     ContentResolver cr = context.getContentResolver();
             Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?", new String[] { ContactsContract.CommonDataKinds.Phone._ID}, null);
             String lname = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));

         Toast.makeText(context, "number is "+lname, Toast.LENGTH_LONG).show();
        }catch (Exception e) {
            // TODO: handle exception
        }

         }
           } 

这是我迄今。在try catch块片code总是崩溃。

it's what I have so far. the piece of code in the try catch block always crashes.

推荐答案

我写了这个方法，最终解决我的问题。

I wrote this method eventually to solve my problem

public String get_Number(String name,Context context)

{String number="";


Uri uri = ContactsContract.CommonDataKinds.Phone.CONTENT_URI;
String[] projection    = new String[] {ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME,
                ContactsContract.CommonDataKinds.Phone.NUMBER};

Cursor people = context.getContentResolver().query(uri, projection, null, null, null);

int indexName = people.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME);
int indexNumber = people.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);

people.moveToFirst();
do {
    String Name   = people.getString(indexName);
    String Number = people.getString(indexNumber);
    if(Name.equalsIgnoreCase(name)){return Number.replace("-", "");}
    // Do work...
} while (people.moveToNext());


if(!number.equalsIgnoreCase("")){return number.replace("-", "");}
else return number;
}

它可能不是非常有效，但嘿它的工作原理

it may not be very efficient but hey it works

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