mysqli问题 [英] Trouble with mysqli
本文介绍了mysqli问题的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我是mysqli函数的新手. 我已经编写了执行简单选择功能的代码. 这是我所做的
I am new to mysqli functions . I have written a code to do the simple select functionality . Here is what I have done
<?php
#---- ini settings(ini)---
ini_set('display_errors', '1');
#---------(/ini)------------
#-------initialisations(init)---
$dbUser = 'myuser';
$dbPass = 'mypass';
$dbhost = 'localhost';
$dbname = 'mydb';
#------------(/init)------------
#---- database connection (db connect)-----
$mysqli = new mysqli($dbhost, $dbUser, $dbPass, $dbname);
$is_error = ($mysqli->connect_errno)?true:false;
if( $is_error )
{
echo $mysqli->connect_error;
}
#-----------------(/ db connect)-----------
/** ------------ queries ---------- **/
$stmt = $mysqli->prepare("SELECT * FROM dept");
if(! $stmt)
{
echo "statement not prepared well";
}
else
{
echo $mysqli->error;
}
if (!$stmt->execute()) {
echo "Execute failed: (" . $stmt->errno . ") " . $stmt->error;
}
if (!($res = $stmt->get_result())) {
echo "Getting result set failed: (" . $stmt->errno . ") " . $stmt->error;
}
/** ------------------------------- **/
#------result ----
var_dump($res->fetch_all());
#---------(/result)----
?>
但是,当我运行此代码时,什么也没有显示,没有错误,没有数据,只是白色的空白页.. 什么我错过了.....?或者我应该如何调试
But When I run this code nothing gets displayed no error , no data just a white blank page .. wht I am missing out ..... ? Or how Should I debug it
提前谢谢.
推荐答案
// change settings for error handler to show errors
// $this setup is used for checking errors for development to be shown....
ini_set('display_errors', 1);
error_reporting(E_ALL);
尝试添加其他内容以查看查询是否成功执行,但没有结果.
Try to add else to see if query is successfuly executed but no result.
if (!$stmt->execute()) {
echo "Execute failed: (" . $stmt->errno . ") " . $stmt->error;
}
// add else
else{
echo "Query is succesfully executed but no result fetch"
}
用该查询替换您的查询以计算数据数量
replace your query by this one to count the number of datas
if ($result = mysqli_query($mysqli, "SELECT * FROM dept")) {
printf("Select returned %d rows.\n", mysqli_num_rows($result));
/* free result set */
mysqli_free_result($result);
}
这篇关于mysqli问题的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
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