如何从服务器获取单个数据到android volley中的textview中? [英] how to fetch single data from server into textview in android volley?
本文介绍了如何从服务器获取单个数据到android volley中的textview中?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我是android的新手，我正在进行登录和密码活动，如果您忘记了密码，则在输入正确的电子邮件后，服务器会将密码发送到textview中，应将其设置为settext.i，这是php文件，但我无法在android中进行编码..我想通过截击获取数据. 这是我的php文件:
i am new to android ,i am working on login and password activity where if you forgot the password then after typing your correct email the server will send the password into textview which should be set as settext.i made the php file but i am unable to made coding in android ..i want the data through volley . here is my php file:
<?php
include ('config.php');
$sql = "SELECT * FROM UserInfo WHERE email='".$email."'";
$r = mysqli_query($con,$sql);
$result = array();
while($row = mysqli_fetch_array($r)){
array_push($result,array(
'password'=>$row['password'],
));
}
echo json_encode(array('result'=>$result));
mysqli_close($con);
?>
这是我的ForgotPassword活动:
here is my ForgotPassword Activity:
public class ForgotPasswordActivity extends AppCompatActivity {
private String fremail;
private ProgressDialog pDialog;
protected EditText femail;
protected Button mSubmitButton;
TextView pas;
private static String url_create_book = "http://cloud.....com/broccoli/fpassword.php";
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_forgot_password);
Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
getSupportActionBar().setDisplayHomeAsUpEnabled(true);
pas=(TextView)findViewById(R.id.pas) ;
femail=(EditText)findViewById(R.id.feml);
Button submit= (Button) findViewById(R.id.sbtn);
submit.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
pDialog = new ProgressDialog(ForgotPasswordActivity.this);
pDialog.setMessage("Please wait..");
pDialog.setIndeterminate(false);
pDialog.setCancelable(true);
pDialog.show();
fremail = femail.getText().toString();
// new CreateNewProduct().execute();
StringRequest stringRequest = new StringRequest(Request.Method.POST, url_create_book,
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
pDialog.dismiss();
try {
JSONObject object = new JSONObject(response);
JSONArray jsonArray = object.getJSONArray("result");
JSONObject jsonObject = jsonArray.getJSONObject(0);
// fetch password from JSON
String password = jsonObject.getString("password");
// use password in textviewfemail.setText(password, TextView.BufferType.EDITABLE);
pas.setText(password, TextView.BufferType.EDITABLE);
}
catch (JSONException e) {
Toast.makeText(ForgotPasswordActivity.this, e.toString(), Toast.LENGTH_LONG).show();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
pDialog.dismiss();
Toast.makeText(ForgotPasswordActivity.this, error.toString(), Toast.LENGTH_LONG).show();
}
}) {
@Override
protected Map<String, String> getParams() {
Map<String, String> params = new HashMap<String, String>();
params.put("email", fremail);
return params;
}
};
RequestQueue requestQueue = Volley.newRequestQueue(ForgotPasswordActivity.this);
requestQueue.add(stringRequest);
}
});
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
switch (item.getItemId()) {
case android.R.id.home:
onBackPressed();
return true;
default:
return super.onOptionsItemSelected(item);
}
}
}
这是我的xml:
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:gravity="center_horizontal"
android:orientation="vertical"
android:paddingBottom="@dimen/activity_vertical_margin"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
tools:context="com.example.zeba.broccoli.Login">
<!-- Login progress -->
<LinearLayout
android:gravity="center_horizontal"
android:orientation="vertical"
android:id="@+id/login_form"
android:layout_width="match_parent"
android:layout_height="match_parent">
<ImageView android:src="@drawable/logobr"
android:layout_width="wrap_content"
android:layout_height="72dp"
android:layout_marginTop="40dp"
android:layout_gravity="center_horizontal" />
<LinearLayout
android:id="@+id/email_login_form"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_marginTop="10dp"
android:orientation="vertical">
<android.support.design.widget.TextInputLayout
android:layout_width="match_parent"
android:layout_height="wrap_content">
<AutoCompleteTextView
android:id="@+id/feml"
android:layout_width="match_parent"
android:hint="email"
android:inputType="textEmailAddress"
android:maxLines="1"
android:singleLine="true"
android:background="@drawable/rounded_edittext"
android:layout_height="40dp"
android:paddingLeft="5dp"
android:layout_marginBottom="20dip"/>
</android.support.design.widget.TextInputLayout>
</LinearLayout>
<Button
android:id="@+id/sbtn"
style="?android:textAppearanceSmall"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_marginTop="16dp"
android:text="Submit"
android:background="@drawable/mybutton"
android:textColor="#fff"
android:textStyle="bold"
android:elevation="0dp" />
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="horizontal"
android:weightSum="1" >
<TextView
android:id="@+id/fpss"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:layout_weight="0.5"
android:gravity="center"
android:layout_marginTop="16dp"
android:text="Your Password is:" />
<TextView
android:id="@+id/pas"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:layout_weight="0.5"
android:gravity="center"
android:layout_marginTop="16dp"
/>
我在logcat中没有收到任何错误，但是当我在设备上运行它时会显示
I am not getting any error in logcat but when i run it on device it shows
jsonException....Index 0 out of 0 range[0...0]
推荐答案
您的PHP代码以JSON格式发送密码，首先对代码中的JSON进行解码并获取密码:
Your PHP code is sending password in JSON format, first decode the JSON in your code and fetch the password:
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
pDialog.dismiss();
try {
JSONObject object = new JSONObject(response);
JSONArray jsonArray = object.getJSONArray("result");
JSONObject jsonObject = jsonArray.getJSONObject(0);
// fetch password from JSON
// UPDATED HERE
String password = jsonObject.getString("password");
femail.setText(password, TextView.BufferType.EDITABLE);
}
catch (JSONException e) {
Toast.makeText(getContext(), e.toString(), Toast.LENGTH_LONG).show();
}
},
PHP
<?php
include ('config.php');
// updated here, value is mapped
$email = $_POST['email'];
$sql = "SELECT * FROM UserInfo WHERE email='".$email."'";
$r = mysqli_query($con,$sql);
//checking if email is valid or not
if(mysqli_fetch_array($r) == NULL){
echo "Invalid email";
}
else{
$result = array();
while($row = mysqli_fetch_array($r)){
array_push($result,array(
'password'=>$row['password'],
));
}
echo json_encode(array('result'=>$result));
}
mysqli_close($con);
?>
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