Myqli PHP登录 [英] Myqli php login

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本文介绍了Myqli PHP登录的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我刚开始使用mysqli,我试图连接到数据库并登录,我收到错误消息,

I have just started using mysqli I'm trying to connect to a database and login, I'm getting the error messages,

注意:未定义的索引:第14行E:\ EasyPHP-DevServer-14.1VC11 \ data \ localweb \ my Portable files \ course work \ login.php中的___ mysqli_ston

Notice: Undefined index: ___mysqli_ston in E:\EasyPHP-DevServer-14.1VC11\data\localweb\my portable files\course work\login.php on line 14

我还试图在表单页面上显示错误消息,而不是创建当前正在执行的新页面.我忘记了PHP是否必须在同一页面上才能显示错误?

I'm also trying to display error messages on the page of the form rather than creating a new page which it's currently doing. I forget does the PHP have to be on the same page for the errors to be displayed?

警告:mysqli_query()期望参数1为mysqli,在第14行的E:\ EasyPHP-DevServer-14.1VC11 \ data \ localweb \ my Portable files \ course work \ login.php中给出空值

Warning: mysqli_query() expects parameter 1 to be mysqli, null given in E:\EasyPHP-DevServer-14.1VC11\data\localweb\my portable files\course work\login.php on line 14

找不到数据库

<?php

session_start();

$username = $_POST['username'];
$password = $_POST['password'];
$errors = array();


if ($username&&$password)
{

$connect = mysqli_connect("localhost","root","") or die ("Could not connect");
((bool)mysqli_query($GLOBALS["___mysqli_ston"], "USE login")) or die ("Could not find database");

$query = mysqli_query($GLOBALS["___mysqli_ston"], "SELECT * FROM users WHERE username ='$username'");

$numrows = mysqli_num_rows($query);
if ($numrows !=0)
{
    while ($row =mysqli_fetch_assoc($query))
    {
        $dbusername = $row['username'];
        $dbpassword = $row['password'];
    }

    if ($username==$dbusername&&$password==$dbpassword)
    {
        echo header( 'Location: member.php' ) ;
        $_SESSION['username']=$dbusername;
        $_SESSION['userid']=$userid;
    }
    else 
        echo "Inncorrect password";

}
else
    die("That user dosen't exist");
}

else
    die("Please enter a username and a password");

?> 

推荐答案

您应该具有mysqli_connect的数据库名称.所以,就这样:

You should have a database name for mysqli_connect. So, go like this:

$connect=mysqli_connect('localhost','root','','databse_name');

以及为什么要使用__mysqli_ston代替?

and why are you using __mysqli_ston for?Use this instead

$query = mysqli_query($connect, "SELECT * FROM users WHERE username='$username'");

请勿使用__mysqli_ston.

这应该可以.如果不起作用,请找我.

This should work.If doesn't work,get back to me.

这篇关于Myqli PHP登录的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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