无法插入在SQLite数据库Android的数据 [英] Unable to insert data in Sqlite Database android

问题描述

继code用于在数据库中插入数据。

Following code is used to insert data in the database.

在启动应用程序时，下面的code被执行。

When application is launched, following code is executed.

在 RecentDBManager 执行时，当我 PULL 从模拟器内存​​数据库，它显示了在<$ C无记录$ C> FavoriteScrip 表。

After RecentDBManager is executed, when I PULL database from emulator memory, it shows no record in FavoriteScrip table.

当我在使用setData 方法记录的insertstmt ，它工作正常。
它显示了

When I logged InsertStmt in setData method, it works fine. It shows

插入FavoriteScrip（符号，CMP，CHG）VALUES（'值1'，'值'，'VALUE3'）

但它没有得到插入表...

在主类

 rdbM = new RecentDBManager(CompanyView.this);
                        try {
                            if (!rdbM.checkDataBase()) {
                                rdbM.createDataBase();
                            }
                            rdbM.openDB();
                            rdbM.setData("value1");
                            rdbM.closeDB();

                        } catch (Exception e) {
                            throw new Error("ERROR in DB Access"+ e.toString());
                    }

RecentDBManager类

    public class RecentDBManager {
    private DatabaseHelper dataHelper;
    private SQLiteDatabase mDb;
    private Context ctx;
    private String DATABASE_PATH = "/data/data/com.mypackage/databases/";
    private static String DATABASE_NAME = "ScripMasterDB";
    private static String TABLE_NAME = "FavoriteScrip";
        private String InsertStmt;
    private static final int DATABASE_VERSION = 1;
    private Cursor cur;

    RecentDBManager(Context ctx) {
        this.ctx = ctx;
        dataHelper = new DatabaseHelper(ctx);
    }

    private static class DatabaseHelper extends SQLiteOpenHelper {
        Context myContext = null;

        public DatabaseHelper(Context context) {
            super(context, DATABASE_NAME, null, DATABASE_VERSION);
            this.myContext = context;
        }

        @Override
        public void onCreate(SQLiteDatabase db) {
        }

        @Override
        public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
            Log.w("DBHelper", "Upgrading database from version " + oldVersion
                    + " to " + newVersion + ", which will destroy all old data");
            onCreate(db);
        }
    }

    public boolean checkDataBase() {
        String myPath = DATABASE_PATH + DATABASE_NAME;
        File f = new File(myPath);
        return f.exists();
    }

    public void createDataBase() {
        openDB();
        try {
            OutputStream myOutput = new FileOutputStream(DATABASE_PATH+ DATABASE_NAME);

            if (mDb.isOpen())
                mDb.close();
            myOutput.flush();
            myOutput.close();

        } catch (Exception e) {
            throw new Error("RecentDbManager Exception - " + e.getMessage());
        }
    }

    public RecentDBManager openDB() throws SQLException {
        mDb = dataHelper.getWritableDatabase();
        return this;
    }

    public void setData(String value1, String value2, String value3) {
                ContentValues cv = new ContentValues();
cv.put("sym", value1);
cv.put("dt_tm", "datetime()");
mDb.insert(TABLE_NAME, null, cv);

        } catch (SQLiteException e) {
            throw new Error("RecentDbManager Exception in inserting data"
                    + e.getMessage());
        }
    }

    public void closeDB() {
        try {
            mDb.close();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

修改

我有一个包含当前日期时间一列。

EDIT

I have one column which contains current datetime.

所以，查询的格式为插入+ TABLE_NAME +（符号，dt_tm）VALUES（'+值1 +'，日期时间（））

我试过

    ContentValues cv = new ContentValues();
cv.put("sym", value1);
cv.put("dt_tm", "datetime()");
mDb.insert(TABLE_NAME, null, cv);

值1 列是越来越插入到表中，但不是日期时间。可以采取什么问题？

value1 column is getting inserted into table but not datetime. What can be the problem?

完成...我用如下：

                Calendar date1 = Calendar.getInstance();
                    SimpleDateFormat dateformatter = new SimpleDateFormat(
                            "dd/MM/yyyy HH:mm:ss");

                    String currentdate = dateformatter.format(date1
                            .getTime());

并通过的currentdate 作为第二个参数。

日Thnx ALL !!!!

THNX ALL !!!!

任何帮助将生命SAVER !!!

推荐答案

尝试

@Override
public void onCreate(SQLiteDatabase db) {
    db.execSQL(Create table Memo (ID INTEGER PRIMARY KEY AUTOINCREMENT, sym TEXT, cmp TEXT, cng TEXT);
}

public void setData(String value1, String value2, String value3) {

            ContentValues cv = new ContentValues();
            cv.put("sym", value1);
            cv.put("cmp", value2);
            cv.put("cng", value3);

            mDb.insert(TABLE_NAME, null, cv);
    }        

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