如何使用XPath忽略名称空间 [英] how to ignore namespaces with XPath
问题描述
我的目标是使用XPath从具有多个名称空间的多个xml文件中提取某些节点.只要我知道名称空间URI，一切都可以正常工作.名称空间名称本身保持不变，但是架构(XSD)有时是客户端生成的，即我不知道.然后基本上剩下三个选择:
My goal is to extract certain nodes from multiple xml files with multiple namespaces using XPath. Everything works fine as long as i know the namespace URIs. The namespace name itself remains constant, but the Schemas (XSD) are sometimes client-generated i.e. unknown to me. Then i am left with basically three choices :
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仅对名称空间使用一种架构，希望没有任何问题(我确定吗?)
use just one schema for the namespace, hoping nothing goes wrong (can i be sure?)
获取文档的子节点，并在第一个具有名称空间URI的节点上查找，希望在那里，然后仅使用URI，并在其上选择正确的URI.可能由于多种原因而出错
get the children nodes of the document and look for the first node with a namespace URI, hoping its there and just use the URI , hoping its the correct one. can go wrong for multiple reasons
以某种方式告诉xpath:看，我不在乎名称空间，只找到具有此名称的所有节点，我什至可以告诉您名称空间的名称，而不仅仅是URI".这是这里的问题...
somehow tell xpath : "look, i dont care about the namespaces, just find ALL nodes with this name, i can even tell you the name of the namespace, just not the URI". And this is the question here...
这不是对许多我的xpath表达式不起作用，因为我不了解名称空间意识"的重申，这里.我知道如何使用名称空间感知.只是不是如何摆脱它.
This is not a reiteration of numerous "my xpath expression doesnt work because i am not aware of namespace awareness" questions as found here or here. I know how to use namespace awareness. Just not how to get rid of it.
推荐答案
您可以使用local-name() XPath函数.而不是选择像这样的节点
You can use the local-name() XPath function. Instead of selecting a node like
/path/to/x:somenode
您可以选择所有节点，并使用正确的本地名称过滤该节点:
you can select all nodes and filter for the one with the correct local name:
/path/to/*[local-name() = 'somenode']
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