PHP-获取特定命名空间中的所有类名 [英] PHP - get all class names inside a particular namespace

问题描述

我想将所有类都放在一个命名空间中.我有这样的东西:

I want to get all classes inside a namespace. I have something like this:

#File: MyClass1.php
namespace MyNamespace;

class MyClass1() { ... }

#File: MyClass2.php
namespace MyNamespace;

class MyClass2() { ... }

#Any number of files and classes with MyNamespace may be specified.

#File: ClassHandler.php
namespace SomethingElse;
use MyNamespace as Classes;

class ClassHandler {
    public function getAllClasses() {
        // Here I want every classes declared inside MyNamespace.
    }
}

我在getAllClasses()中尝试了get_declared_classes()，但是MyClass1和MyClass2不在列表中.

I tried get_declared_classes() inside getAllClasses() but MyClass1 and MyClass2 were not in the list.

我该怎么办?

推荐答案

通用方法是获取项目中所有完全合格的类名(具有完整名称空间的类)，然后按所需的名称空间进行过滤.

The generic approach would be to get all fully qualified classnames (class with full namespace) in your project, and then filter by the wanted namespace.

PHP提供了一些本机函数来获取这些类(get_declared_classes等)，但是它们将无法找到尚未加载的类(包括/require)，因此无法与自动加载器一起正常工作(例如Composer). 这是一个主要问题，因为自动装带器的使用非常普遍.

PHP offers some native functions to get those classes (get_declared_classes, etc), but they won't be able to find classes that have not been loaded (include / require), therefore it won't work as expected with autoloaders (like Composer for example). This is a major issue as the usage of autoloaders is very common.

因此，您最后的选择是自行查找所有PHP文件，然后解析它们以提取其命名空间和类:

So your last resort is to find all PHP files by yourself and parse them to extract their namespace and class:

$path = __DIR__;
$fqcns = array();

$allFiles = new RecursiveIteratorIterator(new RecursiveDirectoryIterator($path));
$phpFiles = new RegexIterator($allFiles, '/\.php$/');
foreach ($phpFiles as $phpFile) {
    $content = file_get_contents($phpFile->getRealPath());
    $tokens = token_get_all($content);
    $namespace = '';
    for ($index = 0; isset($tokens[$index]); $index++) {
        if (!isset($tokens[$index][0])) {
            continue;
        }
        if (T_NAMESPACE === $tokens[$index][0]) {
            $index += 2; // Skip namespace keyword and whitespace
            while (isset($tokens[$index]) && is_array($tokens[$index])) {
                $namespace .= $tokens[$index++][1];
            }
        }
        if (T_CLASS === $tokens[$index][0] && T_WHITESPACE === $tokens[$index + 1][0] && T_STRING === $tokens[$index + 2][0]) {
            $index += 2; // Skip class keyword and whitespace
            $fqcns[] = $namespace.'\\'.$tokens[$index][1];

            # break if you have one class per file (psr-4 compliant)
            # otherwise you'll need to handle class constants (Foo::class)
            break;
        }
    }
}

如果遵循PSR 0或PSR 4标准(您的目录树反映了您的名称空间)，则无需过滤任何内容:只需提供与所需名称空间相对应的路径即可.

If you follow PSR 0 or PSR 4 standards (your directory tree reflects your namespace), you don't have to filter anything: just give the path that corresponds to the namespace you want.

如果您不喜欢复制/粘贴上面的代码片段，则只需安装此库即可: https://github.com/gnugat/nomo-spaco . 如果使用PHP> = 5.5，则还可以使用以下库: https://github.com/hanneskod/classtools .

If you're not a fan of copying/pasting the above code snippets, you can simply install this library: https://github.com/gnugat/nomo-spaco . If you use PHP >= 5.5, you can also use the following library: https://github.com/hanneskod/classtools .

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