使用PHP 5.3名称空间按字符串实例化类 [英] Instantiating class by string using PHP 5.3 namespaces

问题描述

我无法解决通过使用字符串变量和PHP 5.3实例化新类的问题.命名空间.例如，这有效；

I can't get around an issue instantiating a new class by using a string variable and PHP 5.3. namespaces. For example, this works;

$class = 'Reflection';
$object = new $class();

但是，这不是；

$class = '\Application\Log\MyClass';
$object = new $class();

引发致命错误，指出找不到该类.但是，显然可以使用FQN将其实例化；即

A fatal error gets thrown stating the class cannot be found. However it obviously can be instantiated if using the FQN i.e.;

$object = new \Application\Log\MyClass;

我发现这在PHP 5.3.2-1上是相同的，但在更高版本中不是.有没有解决的办法?

I've found this to be aparrent on PHP 5.3.2-1 but not not in later versions. Is there a work around for this?

推荐答案

$class = 'Application\Log\MyClass';
$object = new $class();

开头的\引入了(完全限定的)命名空间标识符，但它不是类名本身的一部分.

The starting \ introduces a (fully qualified) namespaced identifier, but it's not part of the class name itself.

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