python函数可以调用具有相同名称的全局函数吗? [英] can a python function call a global function with the same name?

问题描述

我可以从具有相同名称的函数中调用全局函数吗?

Can I call a global function from a function that has the same name?

例如:

def sorted(services):
    return {sorted}(services, key=lambda s: s.sortkey())

由{sorted}表示全局排序函数. 有没有办法做到这一点? 然后，我想用模块名称调用我的函数:service.sorted(services)

By {sorted} I mean the global sorted function. Is there a way to do this? I then want to call my function with the module name: service.sorted(services)

我想使用相同的名称，因为它与全局函数具有相同的作用，只是它添加了默认参数.

I want to use the same name, because it does the same thing as the global function, except that it adds a default argument.

推荐答案

Python的名称解析方案(有时称为LEGB规则)表示，当您在函数内使用不合格的名称时，Python最多搜索四个范围-首先是本地(L)范围，然后是任何封闭的(E)def和lambda s的本地范围，然后是全局(G)范围，最后是内置的在(B)范围内. (请注意，一旦找到匹配项，它将立即停止搜索)

Python's name-resolution scheme which sometimes is referred to as LEGB rule, implies that when you use an unqualified name inside a function, Python searches up to four scopes— First the local (L) scope, then the local scopes of any enclosing (E) defs and lambdas, then the global (G) scope, and finally the built-in (B) scope. (Note that it will stops the search as soon as it finds a match)

因此，当您在函数解释器中使用sorted时，会将其视为全局名称(您的函数名称)，因此您将拥有递归函数.如果要访问内置的sorted，则需要为Python指定.通过__builtin__模块(在Python-2.x 中为)和 Python-3.x中的> builtins (此模块可直接访问Python的所有内置"标识符)

So when you use sorted inside the functions interpreter considers it as a Global name (your function name) so you will have a recursion function. if you want to access to built-in sorted you need to specify that for Python . by __builtin__ module (in Python-2.x ) and builtins in Python-3.x (This module provides direct access to all ‘built-in’ identifiers of Python)

python 2:

import __builtin__
def sorted(services):
    return __builtin__.sorted(services, key=lambda s: s.sortkey())

python 3:

import builtins
def sorted(services):
    return builtins.sorted(services, key=lambda s: s.sortkey())

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