PHP中的命名空间阻止使用Yii静态函数 [英] Namespaces in PHP preventing using of Yii static functions

问题描述

我只是在我的小型应用程序中实现了命名空间，如下所示: http: //www.yiiframework.com/doc/guide/1.1/zh-CN/basics.namespace

I just implemented namespaces in my small application as outlined here: http://www.yiiframework.com/doc/guide/1.1/en/basics.namespace

我遇到了一个问题，我的控制器将无法再访问Yii::app()->getRequest();，说找不到include(C:\Users\bkuhl\htdocs\instaLabel\application\protected\components\Yii.php): failed to open stream: No such file or directory.

I'm running into an issue where my controller will no longer access Yii::app()->getRequest(); saying it can't find include(C:\Users\bkuhl\htdocs\instaLabel\application\protected\components\Yii.php): failed to open stream: No such file or directory.

我意识到这是因为我将名称空间声明为应用程序/组件.但是我不确定如何解决这个问题...

I realize that's because I declared the namespace as application/components. But I'm not sure how to work around this one...

<?php

namespace application\components;

/**
 * Controller is the customized base controller class.
 * All controller classes for this application should extend from this base class.
 */
class Controller extends \CController {
    /* @var $request CHttpRequest */
    protected $request = null;

    /**
     * @var string the default layout for the controller view. Defaults to '//layouts/column1',
     * meaning using a single column layout. See 'protected/views/layouts/column1.php'.
     */
    public $layout='//layouts/column1';
    /**
     * @var array context menu items. This property will be assigned to {@link CMenu::items}.
     */
    public $menu=array();
    /**
     * @var array the breadcrumbs of the current page. The value of this property will
     * be assigned to {@link CBreadcrumbs::links}. Please refer to {@link CBreadcrumbs::links}
     * for more details on how to specify this property.
     */
    public $breadcrumbs=array();

    public function __construct ($id, $module = null) {
        parent::__construct($id, $module);

        $this->request = Yii::app()->getRequest();
    }

推荐答案

您需要完全限定相对类名称Yii.

You need to fully qualify the relative class name Yii.

最方便的方法是通过导入该类:只需在名称空间声明下方添加use Yii;.

The most convenient way to do this is by importing the class: just add use Yii; below your namespace declaration.

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