从名称空间导出类 [英] Export class from namespace

问题描述

我为类命名空间以使用别名为某些长类名称提供简写:

I namespaced a class to make use of aliases to provide shorthands for some long class names:

namespace some_namespace;
use \VeryLongClassnameWhichIUseOften as Short;

class MyClass {
  public static method do_stuff() {

    Short::do_something(Short::do_other_stuff());

  }
}

现在，某些第三方代码在全局名称空间中要求使用MyClass.

Now there is some third party code that expects MyClass in the global namespace.

我可以以某种方式将MyClass导出到全局名称空间吗?

Can I somehow export MyClass to the global namespace?

我尝试过

class \MyClass {
  ...
}

但是显然这是不允许的(意外的T_NS_SEPARATOR，期望T_STRING).

but apparently that is no allowed (unexpected T_NS_SEPARATOR, expecting T_STRING).

我也尝试过:

namespace some_namespace {
  use \VeryLongClassnameWhichIUseOften as Short;

  class MyClass {
    ...
  }
}

namespace {
  use \some_namespace\MyClass as MyClass;
}

不会引发任何其他错误，但是MyClass在全局命名空间中仍然不可用(找不到类'MyClass').我不太明白为什么.

which doesn't throw any additional error but MyClass still isn't available in the global namespace (Class 'MyClass' not found). I don't quite understand why.

推荐答案

将其放在您的全局命名空间中:

Put this in your global namespace:

use \some_namespace\MyClass as MyClass;

我相信它应该起作用.

否.这应该起作用:

class_alias('\some_namespace\MyClass', 'MyClass');

这篇关于从名称空间导出类的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！