如何在Swift中使用名称为Objective-C的类作为关键字 [英] How to use Objective-C classes with names which are keywords in Swift

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本文介绍了如何在Swift中使用名称为Objective-C的类作为关键字的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我们正在尝试使用BZObjectStore库( https://github.com/expensivegasprices/BZObjectStore )在我们的Swift项目中.

We are trying to use the BZObjectStore library (https://github.com/expensivegasprices/BZObjectStore) in our Swift project.

但是在该库中,它们使用"where"作为名称来设置查询条件.

But in this library, they use 'where' as a name to set the query conditions.

BZObjectStoreConditionModel *fetchCondition = [BZObjectStoreConditionModel condition];
fetchCondition.sqlite.where = @"name = 'sample1' and price > 50";
fetchCondition.sqlite.orderBy = @"name desc";

NSArray *objects = [os fetchObjects:[SampleModel class] condition:fetchCondition error:&error];

但是不幸的是,'where'是Swift中的关键字.我们不想手动更改BZObjectStore中的代码.那么有什么办法可以解决这个问题?

But unfortunately, 'where' is a keyword in Swift. We do not want to change the code in BZObjectStore manually. So is there any way we can resolve this ?

推荐答案

您必须使用反引号:

fetchCondition.sqlite.`where` = @"name = 'sample1' and price > 50";

要将保留字用作标识符,请在其前后加上反引号(`).例如,class不是有效的标识符,但是`class`是有效的.反引号不视为标识符的一部分; x和x具有相同的含义.

To use a reserved word as an identifier, put a backtick (`) before and after it. For example, class is not a valid identifier, but `class` is valid. The backticks are not considered part of the identifier; `x` and x have the same meaning.

Swift编程语言–词法结构

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