通过JSON的答复从web服务的变量 [英] passing json reply from webservice to variables

问题描述

我张贴一些数据到Web服务，我得到我想要传递给一个JSONObject一个JSON答复。

Web服务的答复是：

  {
    ValidateLoginResult：[
        {
            的ErrorMessage：错误的用户名通行证，
            PROPERTYNAME：空
        }
    ]
}
 

和我要传递的错误信息和属性名称变量。我尝试使用的JSONObject和JSONarray但没有任何运气

 的HttpClient HttpClient的=新DefaultHttpClient（）;                // 2.化妆POST请求到指定的URL
                HttpPost httpPost =新HttpPost（serverURL使用）;
                StringEntity本身=新StringEntity（数据）;
                httpPost.setEntity（SE）;                // 7.设置一些头通知服务器有关内容的类型
                httpPost.setHeader（接受，应用/ JSON）;
                httpPost.setHeader（内容类型，应用/ JSON）;                // 8.执行POST请求到指定的URL
                HTT presponse HTT presponse = httpclient.execute（httpPost）;
                // 9.获得回复
                的InputStream = HTT presponse.getEntity（）的getContent（）。
                ...
                ...
                 JSONArray JSON =新JSONArray（convertInputStreamToString（的InputStream））;                的JSONObject json_LL = json.getJSONObject（0）;                串str_value = json_LL.getString（的ErrorMessage）;
 

解决方案

您也越来越在的JSONObject 的反应和你想获得它在 JSONArray ..这就是为什么你得到错误。

试试这个方法...

  {尝试
    JSONObject的结果=新的JSONObject（响应）;    如果（data.has（ValidateLoginResult）{
        JSONArray阵列= result.getJSONArray（ValidateLoginResult）;        的for（int i = 0; I＆LT; array.length（）;我++）{
        JSONObject的OBJ = array.getJSONObject（I）
            串的ErrorMessage =+ obj.getString（的ErrorMessage）;
            字符串属性名=+ obj.getString（属性名）;
        }
    }}赶上（JSONException E）{
    e.printStackTrace（）;
}
 

或

如果你想一行answer..Try这个..

  //直接到数组对象..
的JSONObject结果=新的JSONObject（响应）.getJSONArray（ValidateLoginResult）getJSONObject（0）。串的ErrorMessage =+ result.getString（的ErrorMessage）;
字符串属性名=+ result.getString（属性名）;
 

i'm posting some data to a web service and i'm getting a json reply which i want to pass to a jsonobject.

The reply of the web service is:

{
    "ValidateLoginResult": [
        {
            "ErrorMessage": "Wrong username pass",
            "PropertyName": null
        }
    ]
}

and i want to pass the error message and the property name to variables. I tried using JSONobject and JSONarray but didnt have any luck

                HttpClient httpclient = new DefaultHttpClient();

                // 2. make POST request to the given URL
                HttpPost httpPost = new HttpPost(serverURL);
                StringEntity se = new StringEntity(data);
                httpPost.setEntity(se);

                // 7. Set some headers to inform server about the type of the content
                httpPost.setHeader("Accept", "application/json");
                httpPost.setHeader("Content-type", "application/json");

                // 8. Execute POST request to the given URL
                HttpResponse httpResponse = httpclient.execute(httpPost);
                // 9. Getting Reply
                inputStream = httpResponse.getEntity().getContent();
                ...
                ...
                 JSONArray json = new JSONArray(convertInputStreamToString(inputStream));



                JSONObject json_LL = json.getJSONObject(0);

                String str_value=json_LL.getString("ErrorMessage");

解决方案

You are getting response in JSONObject and you are trying to get it in JSONArray.. thats why you are getting error..

Try this way...

try {
    JSONObject result = new JSONObject(response);

    if(data.has("ValidateLoginResult"){
        JSONArray array = result.getJSONArray("ValidateLoginResult");

        for (int i = 0; i < array.length(); i++) {
        JSONObject obj = array.getJSONObject(i);
            String ErrorMessage= ""+obj.getString("ErrorMessage");
            String PropertyName= ""+obj.getString("PropertyName");
        }
    }

} catch (JSONException e) {
    e.printStackTrace();
}

OR

if you want one line answer..Try this..

// going directly to array object..
JSONObject result = new JSONObject(response).getJSONArray("ValidateLoginResult").getJSONObject(0);

String ErrorMessage= ""+result.getString("ErrorMessage");
String PropertyName= ""+result.getString("PropertyName");

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