打印“数组"来自gdb中的.bss [英] Printing "array" from .bss in gdb

问题描述

我的nasm x86汇编代码包含以下内容:

my nasm x86 assembly code contains the following:

; The code should mimic the following C-code:
; int a[10];
; for (int i = 0; i < 10; i++){
;    a[i] = i;
; }

SECTION .data
    arraylen dd 10
SECTION .bss
    array RESD 10
SECTION .text
    global main
main:
    mov ecx, 0
    mov eax, 0
loop:
    inc ecx
    mov dword [array+eax*4], ecx
    inc eax
    cmp ecx, arraylen
    jl loop
end:
    mov ebx, 0
    mov eax, 1
    int 0x80

现在我要检查的是此代码是否在gdb中有效. 但是，我如何打印array?

Now what i want is to check whether this code works in gdb. However, how do i print array?

print array仅返回$1 = 1.

print array + X不幸的是算术运算，即 例如print array + 50实际上打印1 + 50 = 51而不是不存在的第51个数组元素.

print array + X unfortunately is an arithmetical operation, i.e. e.g. print array + 50 actually prints 1+50 = 51 and not the non-existent 51st array element.

推荐答案

您可以这样做:

(gdb) x/10 &array
0x8049618:      1       2       3       4
0x8049628:      5       6       7       8
0x8049638:      9       10

PS:您的代码已损坏，需要cmp ecx, [arraylen].

PS: Your code is broken, you need cmp ecx, [arraylen].

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