Nativescript和资源文件夹-有一个简单的解决方案吗? [英] Nativescript and resources folder - is there a simple solution?

问题描述

我将从当前的事实开始-我上传成功 mp3文件发送到服务器-但是通过黑客方式.

I will start with the fact that currently - I'm uploading successfully an mp3 file to a server - but via a hacky way.

如您所见，我有2个raw文件夹:

I'm having 2 raw folders as you can see :

这是上传文件的工作代码:

And here is the working code to upload the file :

 upload1()
    {

        let file = fs.path.join(fs.knownFolders.currentApp().path, "raw/a1.mp3");

        var request = {
            url:         "http://posttestserver.com/post.php",
            method:      "POST",
            ...
        };

        var task = session.uploadFile(file, request);
        task.on("progress", this.logEvent);

    }

以下是成功上传(显示进度)的输出

那么问题出在哪里?

当前文件是从根raw文件夹上载的. (证明)

The current file is being uploaded from the root raw folder. (proof)

但是正确的方法( as有人告诉我 )是通过raw文件夹或assets文件夹上传它，然后通过res://raw/a1.mp3(或res://raw/a1)引用它.

But the right way (as I was told)is to upload it via the raw folder or the assets folder and then reference it via res://raw/a1.mp3 ( or res://raw/a1).

所以我切换到了let file="res://raw/a1.mp3";

但是出现了 错误 :

But got an error:

错误错误:java.io.FileNotFoundException:在以下位置找不到文件 路径:res://raw/a1.mp3

ERROR Error: java.io.FileNotFoundException: Could not find file at path: res://raw/a1.mp3

也用于:let file="res://raw/a1"; //without extension-出现错误:

JS:错误错误:java.io.FileNotFoundException:在以下位置找不到文件 路径:res://raw/a1

JS: ERROR Error: java.io.FileNotFoundException: Could not find file at path: res://raw/a1

问题:
如何访问raw文件夹下的mp3文件? (不是外部文件夹，而是资源文件夹)

Question:
How can I access the mp3 file under the raw folder? (not the outside folder but the resource one)

推荐答案

我不熟悉NativeScript，但是这里有一个示例，说明了如何使用Java访问原始文件夹文件，而无论其类型如何:

I am unfamiliar with NativeScript but here is an example of how to access the raw folder files regardless of type using Java:

public static final FileDescriptor getFDForResource(Context context, int resId) {
     AssetFileDescriptor afd = context.getResources().openRawResourceFd(resId);
     if (afd != null) {
        return afd.getFileDescriptor();
     }
     return null;
}

public void readFile(int resId) {
    FileDescriptor fd = getFDForResource(resId);
    InputStream inputStream
    if(fd != null) {
        inputStream = new FileInputStream(fd);
        byte nextByte;
        while((nextByte = inputStream.read()) != -1) {
            // Upload the file bytes to your server.
        }
    }
}

您想将此代码放在Util类中，并使用NativeScript进行访问.我敢肯定有一些API可以做到这一点，但是我不熟悉我能提供的一切.

You'll wanna place this code in a Util class and access it using NativeScript. I'm sure there is some API to do such a thing but being I am unfamiliar that is all I can provide.

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