Python3 +诅咒:如何按"q"立即结束程序? [英] Python3 + Curses: How to press "q" for ending program immediately?

问题描述

当我运行以下示例代码并仅按"q"时，它将正确结束， 但是如果我按任何其他字符例如很多休息和许多其他字符"，然后按"q"，它不会退出，我该如何解决呢?

When I run the following sample code and press just "q", it'll ends properly, but if I pressed any other characters "for instance many breaks and a lot of other characters" and then press "q" it'll not exit, how can I solve this?

import curses, time

def main(sc):
    sc.nodelay(1)

    while True:
        sc.addstr(1, 1, time.strftime("%H:%M:%S"))
        sc.refresh()

        if sc.getch() == ord('q'):
            break

        time.sleep(1)

if __name__=='__main__': curses.wrapper(main)

推荐答案

按下其他键会导致time.sleep(1)调用，您应该等待n秒(n =其他按键次数).

Pressing other keys cause time.sleep(1) call, you should wait n seconds (n = number of other key strokes).

删除time.sleep呼叫将解决您的问题.

Removing time.sleep call will solve your problem.

def main(sc):
    sc.nodelay(1)

    while True:
        sc.addstr(1, 1, time.strftime("%H:%M:%S"))
        sc.refresh()

        if sc.getch() == ord('q'):
            break

        #time.sleep(1) <------

替代方法:有条件地调用time.sleep(仅当未按下任何键时，如果在非阻塞模式下未按下任何键，则getch返回-1):

Alternative: call time.sleep conditionally (only when no key was pressed, getch returns -1 if no key was pressed in non-blocking mode):

while True:
    sc.addstr(1, 1, time.strftime("%H:%M:%S"))
    sc.refresh()

    key = sc.getch()
    if key == ord('q'):
        break
    elif key < 0:
        time.sleep(1)

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