Neo4j:在Neo4j Rest或通过Cypher检索连接到节点的所有节点和关系 [英] Neo4j : Retrieving All Nodes and Relationship connected to a Node in Neo4j Rest OR through Cypher
问题描述
我想检索所有节点以及连接到节点的关系.
I want to Retrieve all nodes and relationship connected to a node.
我试图通过两种方式做到这一点:
I Tried to do this in two ways:
第一通过 Neo4j REST API 我尝试过
URI traverserUri = new URI( startNode.toString() + "/traverse/node" );
WebResource resource = Client.create()
.resource( traverserUri );
String jsonTraverserPayload = t.toJson();
ClientResponse response = resource.accept( MediaType.APPLICATION_JSON )
.type( MediaType.APPLICATION_JSON )
.entity( jsonTraverserPayload )
.post( ClientResponse.class );
System.out.println( String.format(
"POST [%s] to [%s], status code [%d], returned data: "
+ System.getProperty( "line.separator" ) + "%s",
jsonTraverserPayload, traverserUri, response.getStatus(),
response.getEntity( String.class ) ) );
response.close();
并获得以下响应:
[ {
"outgoing_relationships" : "http://localhost:7474/db/data/node/82/relationships/out",
"data" : {
"band" : "The Clash",
"name" : "Joe Strummer"
},
"traverse" : "http://localhost:7474/db/data/node/82/traverse/{returnType}",
"all_typed_relationships" : "http://localhost:7474/db/data/node/82/relationships/all/{-list|&|types}",
"property" : "http://localhost:7474/db/data/node/82/properties/{key}",
"all_relationships" : "http://localhost:7474/db/data/node/82/relationships/all",
"self" : "http://localhost:7474/db/data/node/82",
"properties" : "http://localhost:7474/db/data/node/82/properties",
"outgoing_typed_relationships" : "http://localhost:7474/db/data/node/82/relationships/out/{-list|&|types}",
"incoming_relationships" : "http://localhost:7474/db/data/node/82/relationships/in",
"incoming_typed_relationships" : "http://localhost:7474/db/data/node/82/relationships/in/{-list|&|types}",
"create_relationship" : "http://localhost:7474/db/data/node/82/relationships"
}, {
"outgoing_relationships" : "http://localhost:7474/db/data/node/83/relationships/out",
"data" : {
}]
但是问题是,如果我想再次查看该节点的关系,我将不得不点击链接"http://localhost:7474/db/data/node/82/relationships/all"
But the problem is if i want to see the relationship of this node again i will have to hit the link "http://localhost:7474/db/data/node/82/relationships/all"
无法获得其中直接显示Node及其关系而不是链接至关系而不再次单击链接的数据吗??
Cant we get Data in which Node and its relationship are shown directly instead of link to relationship without hitting the link again????
第二个事情是从密码查询中获取此信息:
2nd thing I have tried to do is to get this from cypher query :
START a=node(3)
MATCH (a)-[:KNOWS]->(b)-[:KNOWS]->(c)-[:KNOWS]->(d)
RETURN a,b,c,d
但这也没有用,因为在(b)
和(c)
处将有多个值,因此我必须迭代并编写另一个查询
But this also didn't work because at (b)
and (c)
there will be multiple values as a result for which i will have to iterate and write another query
我们无法在单个查询中完成此操作,因为我有许多联系关系,因此很难一次又一次地进行迭代.任何帮助都会得到体现.
Cant we get this done in single query because i have so many connected relationship that it is getting hard to iterate again and again. Any Help would be Appreaciated.
推荐答案
使用Cypher轻松将所有节点连接到给定节点
It's easy to get all nodes connected to a given node with Cypher
START a=node(3)
MATCH (a)-[:KNOWS*]->(d)
RETURN distinct d
但是,如果您有大量连接的节点和深层连接,则可能无法获得良好的性能.
But if you have large number of connected nodes and deep connections, you might not get a good performance.
如果您知道连接的范围,请在查询中明确指定它对性能有帮助,
If you know the bounds of the connections, specify it explicitly in the query would be helpful for performance,
START a=node(3)
MATCH (a)-[:KNOWS*1..3]->(d)
RETURN Distinct d
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