运行参数化Neo4j密码查询 [英] Running parametrized neo4j cypher query

问题描述

以下给出的密码查询将针对参数化列表中提到的每种关系类型重复进行，并且每种关系类型都有要添加到连接节点的特定属性和值.根据neo4j，无法参数化关系类型.反正有使用密码解决这个问题吗?或与apoc?

Given below is the cypher query which gets repeated for each relationship type as mentioned in parameterized list and each relationship type has specific property and value to be added to the connecting node. According the neo4j, it is not possible to parametrize relationship type. Is there anyway to address this using cypher? or with apoc?

Merge(n_device: Device{identifier: {deviceId}}) ON CREATE SET n_device.created=timestamp()
WITH n_device
OPTIONAL MATCH (n_device)-[r_prev:{deviceRel}{active:true}]->() 
WITH n_device, r_prev   
Merge(n_deviceOs: Device{{deviceRelProp}: {deviceRelPropVal}}) ON CREATE SET n_deviceOs :DeviceOs,  n_deviceOs.created=timestamp(), n_deviceOs.newNode=true
WITH n_device, n_deviceOs, r_prev
Merge (n_device)-[r_cur:{deviceRel}]->(n_deviceOs) ON CREATE SET r_cur.active=true, r_cur.created=timestamp()
WITH n_deviceOs, r_prev
Match(n_deviceOs) where n_deviceOs.newNode=true set r_prev.active = false, r_prev.modified=timestamp()
REMOVE n_deviceOs.newNode

"params": {
    "deviceId": "1234",
    "deviceRel": ["HAS_DEVICE_OS", "HAS_DEVICE_OSINFO", "HAS_DEVICE_MODEL", "HAS_DEVICE_APPVERSION"],
    "deviceRelProp": ["os", "osinfo", "model", "version"],
    "deviceRelPropVal": ["android", "kitkat", "samsung", "1.64.2"]
}

推荐答案

Neo4j无法使用参数化类型创建关系.但是有一个APOC程序可以做到这一点.请参见创建数据部分，apoc.create.relationship()为您正在寻找的过程.

Neo4j can't create a relationship with a parameterized type. But there is an APOC Procedure which allows this. See the creating data section, apoc.create.relationship() is the procedure you're looking for.

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