在R中嵌套列表的元素上逐个元素地添加列表 [英] append a list element-wise to elements of a nested list in R

问题描述

我是R的新手，但我仍然想让自己绕过apply系列，而不是使用循环.

I'm new to R and still trying to get my head around the apply family instead of using loops.

我有两个列表，一个嵌套，另一个不嵌套，都由字符组成:

I have two lists, one nested, the other not, both composed of characters:

>lst1 <- list(c("ABC", "DEF", "GHI"), c("JKL", "MNO", "PQR"))
>lst2 <- c("abc", "def")

我想创建第三个列表，以便将lst2的每个元素附加为lst1中各个子列表的最后一个元素.所需的输出如下所示:

I would like to create a third list such that each element of lst2 is appended as the last element of the respective sublist in lst1. The desired output looks like this:

>lst3
[[1]]
[1] "ABC" "DEF" "GHI" "abc"

[[2]]
[1] "JKL" "MNO" "PQR" "def"

到目前为止，我在R中的经验告诉我，可能有一种无需明确编写循环即可完成此操作的方法.

My experience thus far in R tells me there likely is a way of doing this without writing a loop explicitly.

推荐答案

您可以使用Map来完成mapply(..., simplify = F)的作用:

You can use Map which does exactly what mapply(..., simplify = F) do:

Map(c, lst1, lst2)
[[1]]
[1] "ABC" "DEF" "GHI" "abc"

[[2]]
[1] "JKL" "MNO" "PQR" "def"

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