如何保持套接字打开，直到客户端关闭它? [英] How to keep a socket open until client closes it?

问题描述

我有简单的python服务器和客户端.

I have simple python server and client.

服务器:

import SocketServer
import threading


class MyTCPHandler(SocketServer.BaseRequestHandler):
    def handle(self):
        self.data = self.request.recv(1024).strip()
        print str(self.client_address[0]) + " wrote: "
        print self.data
        self.request.send(self.data.upper())


if __name__ == "__main__":
    HOST, PORT = "localhost", 3288
    server = SocketServer.TCPServer((HOST, PORT), MyTCPHandler)
    server.serve_forever()

客户:

import socket
import sys
from time import sleep

HOST, PORT = "localhost", 3288
data = "hello"

sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

try:
    sock.connect((HOST, PORT))
    sock.send(data + "\n")
    received = sock.recv(1024)

    sleep(10)

    sock.send(data + "\n")
    received = sock.recv(1024)

    sleep(10)

    sock.send(data + "\n")
    received = sock.recv(1024)

finally:
    sock.close()

这是我得到的输出:

服务器:

>python server.py
127.0.0.1 wrote:
hello

客户:

>python client.py
Traceback (most recent call last):
  File "client.py", line 18, in <module>
    received = sock.recv(1024)
socket.error: [Errno 10053] An established connection was aborted by the software in your host machine

我也在Linux机器上尝试过.服务器仅收到一条消息，然后第二条消息的recv语句出现错误.我刚刚开始在python上学习网络，但是我认为服务器由于某种原因正在关闭套接字.我该如何纠正?

I tried it on a linux machine as well. The server only receives one message and then I get an error on the recv statement of second message. I have just started learning networking on python but I think the server is closing the socket for some reason. How do I correct this?

推荐答案

为每个连接创建一个MyTcpHandler对象，并调用handle来处理客户端. handle返回时，连接将关闭，因此您必须在handle方法中处理来自客户端的完整通信:

A MyTcpHandler object is created for each connection, and handle is called to deal with the client. The connection is closed when handle returns, so you have to handle the complete communication from the client within the handle method:

class MyTCPHandler(SocketServer.BaseRequestHandler):
    def handle(self):
        while 1:
            self.data = self.request.recv(1024)
            if not self.data:
                break
            self.data = self.data.strip()
            print str(self.client_address[0]) + " wrote: "
            print self.data
            self.request.send(self.data.upper())

注意:当客户端关闭连接时，recv返回''，所以我将.strip()移到了recv之后，因此不会出现错误警报，因为客户端仅发送空白.

NOTE: recv returns '' when the client closes the connection, so I moved .strip() after the recv so there is no false alarm due to the client sending only white space.

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