socket.send在回显客户端的python代码中仅工作一次 [英] socket.send working only once in python code for an echo client

问题描述

我有一个 echo客户端的以下代码，该代码使用套接字连接将数据发送到 echo服务器:

I have the following code for an echo client that sends data to an echo server using socket connection:

echo_client.py

import socket

host = '192.168.2.2'
port = 50000
size = 1024

def get_command():
    #..Code for this here

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((host,port))
while 1:
    msg = get_command()
    if msg == 'turn on':
        s.send('Y')
    elif msg == 'turn off':
        s.send('N')
    elif msg == 'bye bye':
        break   
    else:
        s.send('X') 
    data = s.recv(size)
    print 'Received: ',data

s.close()

echo_server.py

import socket 

host = '' 
port = 50000 
backlog = 5 
size = 1024 
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) 
s.bind((host,port)) 
s.listen(backlog) 
while 1: 
    client, address = s.accept() 
    data = client.recv(size) 
    if data: 
        client.send(data) 
client.close()

面临的问题是，在客户端中， send.send仅在第一次运行时有效，即使它处于无限循环中也是如此. .在第一次发送/接收完成后的一段时间内，连接超时，客户端崩溃.

The problem im facing is that in the client s.send works only the first time even though its in an infinite loop. The client crashes with connection timed out, some time after the first send/receive has completed.

为什么s.send只工作一次?如何在我的代码中解决此问题?

Why is s.send working only once ?. How can i fix this in my code ?

请帮助 谢谢

推荐答案

您的服务器代码仅调用recv一次.如果只想接收一个连接，则应该调用一次accept，但是随后需要循环调用recv和send.

Your server code only calls recv once. You should call accept once if you only want to receive one connection, but then you need to loop calling recv and send.

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