Networkx:如何在图形图中显示节点和边的属性 [英] Networkx: how to show node and edge attributes in a graph drawing

问题描述

我有一个图G，其节点和边的属性为状态".我想绘制图形，标记所有节点，并在相应的边/节点外部标记状态.

I have a graph G with attribute 'state' for nodes and edges. I want to draw the graph, all nodes labelled, and with the state marked outside the corresponding edge/node.

for v in G.nodes():     
    G.node[v]['state']='X'
G.node[1]['state']='Y' 
G.node[2]['state']='Y'

for n in G.edges_iter():    
    G.edge[n[0]][n[1]]['state']='X'
G.edge[2][3]['state']='Y'

命令draw.networkx具有标签选项，但是我不明白如何为该命令提供属性作为标签.有人可以帮我吗?

The command draw.networkx has an option for labels, but I do not understand how to provide the attribute as a label to this command. Could someone help me out?

推荐答案

虽然不是很漂亮-但它的工作方式如下:

It's not so pretty - but it works like this:

from matplotlib import pyplot as plt
import networkx as nx
G = nx.Graph()
G.add_edge(1,2)
G.add_edge(2,3)
for v in G.nodes():
    G.node[v]['state']='X'
G.node[1]['state']='Y'
G.node[2]['state']='Y'

for n in G.edges_iter():
    G.edge[n[0]][n[1]]['state']='X'
G.edge[2][3]['state']='Y'

pos = nx.spring_layout(G)

nx.draw(G, pos)
node_labels = nx.get_node_attributes(G,'state')
nx.draw_networkx_labels(G, pos, labels = node_labels)
edge_labels = nx.get_edge_attributes(G,'state')
nx.draw_networkx_edge_labels(G, pos, labels = edge_labels)
plt.savefig('this.png')
plt.show()

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