返回属性名称Networkx Python [英] Return attribute name Networkx Python

问题描述

使用此数据:

G.node['node']['a']['initial'] = 100
G.node['node']['a']['final'] = 10

G.node['node']['a']['initial'] = 500
G.node['node']['b']['final'] = 15

我需要进行以下计算:

min(G.node[node]['a']['final'],G.node[node]['b']['final']) / the initial attribute of the node that has the min final value. 
= 10/100

我不知道该告诉谁python 10属于节点G.node ['node'] ['a'].谢谢！

I do not know who to tell python that 10 belongs to the node G.node['node']['a']. Thanks!

推荐答案

您可以使用min函数的key参数来执行此操作.

You can use the key parameter of min function to do this.

min_node = min(['a', 'b'], key=lambda x: G.node['node'][x]['final'])
result = G.node['node'][min_node]['final'] / G.node['node'][min_node]['initial']

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