替换换行符，但保留空白行 [英] Replace newlines, but keep the blank lines

问题描述

我想用空格替换换行符(\ r \ n)，但我想保留空白行.换句话说，如果\ r \ n之前没有另一个\ r \ n，我想用''替换\ r \ n.例如:

I want to replace newlines (\r\n) with space, but I want to keep the blank lines. In other words, I want to replace \r\n with ' ', if \r\n is not preceded by another \r\n. For example:

line 1

line 2
line 3
line 4

终端最终显示为...

Shold end up as...

line 1

line 2 line 3 line 4

但不是第1行，第2行，第3行，第4行"，这就是我现在正在做的事情

But not as "line 1 line 2 line 3 line 4", which is what I'm doing right now with this

preg_replace("/\r\n/", " ", $string);

推荐答案

尝试一下:

(?<!\n)\n(?!\n)

当然，您可以将\n更改为所需的任何内容.

Of course, you can change \n to whatever you need.

工作示例: http://ideone.com/dF5L9

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