在UNIX/Linux操作系统下，如何用sed替换换行(\ n)模式? [英] How to replace a pattern with newline (\n) with sed under UNIX / Linux operating systems?

问题描述

我有一个txt文件，其中包含:

I have a txt file which contains:

Some random
text here. This file
has multiple lines. Should be one line.

我使用:

sed '{:q;N;s/\n/:sl:/g;t q}' file1.txt > singleline.txt

并获得:

Some random:sl:text here. This file:sl:has multiple lines. Should be one line.

现在我想用newline (\n)字符替换:sl:模式.当我使用时:

Now I want to replace the :sl: pattern with newline (\n) character. When I use:

sed 's/:sl:/&\n/g' singleline.txt

我得到:

Some random:sl:
text here. This file:sl:
has multiple lines. Should be one line.

如何用换行符替换模式，而不是在模式后添加换行符?

How to replace the pattern with newline character instead of adding newline character after the pattern?

推荐答案

Sed使用&作为匹配模式的快捷方式.因此，您要用:s1:\n替换:s1:.

Sed uses & as a shortcut for the matched pattern. So you are replacing :s1: with :s1:\n.

像这样更改您的sed命令:

Change your sed command like this:

sed 's/:sl:/\n/g' singleline.txt

这篇关于在UNIX/Linux操作系统下，如何用sed替换换行(\ n)模式?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！