按属性以ng-repeat中的整数值过滤对象数组 [英] Filter array of objects by attribute with integer value in ng-repeat

问题描述

我有这样的指令

ng-repeat="place in tb_places | filter:{'id':inputID}"

输出一些对象数组看起来像这样

to output some array of objects looks like this

$scope.tb_places = [
{name: 'some1', id:1}
...
{name: 'some10', id:10}
{name: 'some11', id:11}
{name: 'some12', id:12} 
...
]

当我更改inputID并将其设置为1时，结果数组将填充源数组的"ids"分别为1和10,11,12的元素.因此，"id"值的一部分像子字符串一样进行检查，而不是数字. 我该怎么治?

when i change the inputID and set it equal to 1, the result array fills with elements of source array with 'ids' of 1 and 10,11,12. Thus, the part of 'id' value is checked like substrings, not a numbers. How can i cure it?

谢谢！

UPD 我试图在过滤器表达式中添加:true"-它将完全清除输出(结果数组)，它适用于简单的字符串数组，但不适用于对象("true"希望与模式对象完全匹配，这意味着所有属性)

UPD i've tried to add ":true" in filter expression - it completely clears output (result array), It works for a simple array of strings, but not the objects ("true" wants exact match with pattern object, it means with all its properties)

解决了！

对不起，我的错！ "inputID"的类型与"id"(字符串与int)的类型不同，因此内置比较器(:true")返回false.非常感谢！

Sorry guys, my fault! 'inputID' was not the same type, as 'id' (string vs int), so built-in comparator (":true") returns false. Many thanks!

ps 抱歉，我不能为您投票-声誉欠佳...见！！

ps sorry, i can't vote for you answers - lack of reputation ... see you!

推荐答案

您需要按照

You need to add the comparator as per the angular filter to achieve your requirement.

您可以将代码更改为:

ng-repeat="place in tb_places | filter: {'id' : inputID} : true"

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