在R中分割字串 [英] Splitting strings in R
问题描述
我有以下一行
x<-"CUST_Id_8Name:Mr.Praveen KumarDOB:Mother's Name:Contact Num:Email address:Owns Car:Products held with Bank:Company Name:Salary per. month:Background:"
我想提取"CUST_Id_8","Praveen Kumar先生"以及在DOB之后写的任何东西:母亲的名字:Contact Num:等等,存储在诸如客户ID,姓名,DOB等变量中.
I want to extract "CUST_Id_8", "Mr. Praveen Kumar" and anything written after DOB: Mother's name: Contact Num: and so on stored in variables like Customer Id, Name, DOB and so on.
请帮助.
我用过
strsplit(x, ":")
但是结果是一个包含文本的列表.但是,如果变量名后面没有任何内容,则需要空格.
But the result is a list containing the texts. But I need blanks if there is nothing after the variable name.
any1能否告诉您如何提取两个单词之间的字符串.就像我想在Name:和DOB之间提取"Praveen Kumar先生"
Can any1 tell how to extract the string between two words. Like if I want to extract "Mr. Praveen Kumar" between Name: and DOB
推荐答案
您可以使用regexec
和regmatches
提取各种数据项作为子字符串.这是一个可行的示例:
You can use regexec
and regmatches
to pull out the various data items as substrings. Here's a worked example:
样本数据
txt <- c("CUST_Id_8Name:Mr.Praveen KumarDOB:Mother's Name:Contact Num:Email address:Owns Car:Products held with Bank:Company Name:Salary per. month:Background:",
"CUST_Id_15Name:Mr.Joe JohnsonDOB:01/02/1973Mother's Name:BarbaraContact Num:0123 456789Email address:joe@joesville.comOwns Car:YesProducts held with Bank:Savings, CurrentCompany Name:Joes villeSalary per. month:$100000Background:shady")
要匹配的模式:
pattern <- "CUST_Id_(.*)Name:(.*)DOB:(.*)Mother's Name:(.*)Contact Num:(.*)Email address:(.*)Owns Car:(.*)Products held with Bank:(.*)Company Name:(.*)Salary per. month:(.*)Background:(.*)"
var_names <- strsplit(pattern, "[:_]\\(\\.\\*\\)")[[1]]
进行比赛:
data <- as.data.frame(do.call("rbind", regmatches(txt, regexec(pattern, txt))))[, -1]
colnames(data) <- var_names
输出:
# CUST_Id Name DOB Mother's Name Contact Num
#1 8 Mr.Praveen Kumar
#2 15 Mr.Joe Johnson 01/02/1973 Barbara 0123 456789
# Email address Owns Car Products held with Bank Company Name
#1
#2 joe@joesville.com Yes Savings, Current Joes ville
# Salary per. month Background
#1
#2 $100000 shady
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