在Python中搜索Unicode字符 [英] Searching for Unicode characters in Python
问题描述
我正在基于Python/NLTK的NLP项目中使用非英语unicode文本.为此,我需要在句子中搜索unicode字符串.
I'm working on a NLP project based on Python/NLTK with non-english unicode text. For that, I need to search unicode string inside a sentence.
有一个 .txt 文件,其中保存了一些非英语的unicode句子.我使用NLTK PunktSentenceTokenizer 破坏了它们并将其保存在python列表中.
There is a .txt file saved with some non-english unicode sentences. Using NLTK PunktSentenceTokenizer i broke them and saved in a python list.
sentences = PunktSentenceTokenizer().tokenize(text)
现在,我可以遍历列表并分别获取每个sentence
.
Now i can iterate through list and get each sentence
separately.
我需要做的是通过sentence
并确定哪个单词具有给定的unicode字符.
What i need to do is go through that sentence
and identify which word has the given unicode characters.
示例-
sentence = 'AASFG BBBSDC FEKGG SDFGF'
假设上面的文本是非英语unicode,我需要找到以GF
结尾的单词,然后返回整个单词(可能是该单词的索引).
Assume above text is non-english unicode and i need to find words ending with GF
then return whole word (may be index of that word).
search = 'SDFGF'
类似地,我需要找到以BB
开头的单词.
Similarly i need to find words starting with BB
get the word of it.
search2 = 'BBBSDC'
推荐答案
如果我理解正确,您只需要将句子拆分为单词,循环遍历每个单词,并检查它是否以所需字符结尾或以例如字符开头:
If I understand correctly, you just have to split up the sentence into words, loop over each one and check if it ends or starts with the required characters, e.g:
>>> sentence = ['AASFG', 'BBBSDC', 'FEKGG', 'SDFGF']
>>> [word for word in sentence.split() if word.endswith("GF")]
['SDFGF']
sentence.split()
可能会替换为nltk.tokenize.word_tokenize(sentence)
更新,关于评论:
如何在单词的前面和后面得到单词
How can get word in-front of that and behind it
enumerate
函数可用于为每个单词赋予一个数字,如下所示:
The enumerate
function can be used to give each word a number, like this:
>>> print list(enumerate(sentence))
[(0, 'AASFG'), (1, 'BBBSDC'), (2, 'FEKGG'), (3, 'SDFGF')]
然后,如果您执行相同的循环,但保留索引:
Then if you do the same loop, but preserve the index:
>>> results = [(idx, word) for (idx, word) in enumerate(sentence) if word.endswith("GG")]
>>> print results
[(2, 'FEKGG')]
..您可以使用索引获取下一个或上一个项目:
..you can use the index to get the next or previous item:
>>> for r in results:
... r_idx = r[0]
... print "Prev", sentence[r_idx-1]
... print "Next", sentence[r_idx+1]
...
Prev BBBSDC
Next SDFGF
您需要处理第一个或最后一个单词(if r_idx == 0
,if r_idx == len(sentence)
)匹配的情况
You'd need to handle the case where the match the very first or last word (if r_idx == 0
, if r_idx == len(sentence)
)
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