在node.JS中，我如何获得通过require不是*我的(即在某些node_module中)加载的模块的路径 [英] In node.JS how can I get the path of a module I have loaded via require that is *not* mine (i.e. in some node_module)

问题描述

我需要一个通过npm安装的模块.我想访问从属于该模块的.js文件(因此我可以在其中继承一个Constructor方法).我不能(当然，不想)修改模块的代码，所以没有地方提取其__dirname.

I require a module that was installed via npm. I want to access a .js file subordinate to that module (so I can subclass a Constructor method in it). I can't (well, don't want to) modify the module's code, so don't have a place to extract its __dirname.

我知道以下问题，但这是关于获得代码控制模块的路径的(因此，__dirname是解决方案): 在Node.js中我该如何分辨此模块的路径?

I am aware of the following question, but it is about getting the path of a module that one has code control over (hence, __dirname is the solution): In Node.js how can I tell the path of `this` module?

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更好的办法是获取模块的已加载模块信息

Even better would be to get the module's loaded module info

推荐答案

如果我正确理解了您的问题，则应使用 require.resolve():

If I correctly understand your question, you should use require.resolve():

使用内部的require()机制查找模块的位置，而不是加载模块，只需返回已解析的文件名即可.

Use the internal require() machinery to look up the location of a module, but rather than loading the module, just return the resolved filename.

示例:var pathToModule = require.resolve('module');

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