在Node.js中检测CTRL + C [英] Detecting CTRL+C in Node.js

问题描述

我从另一个SO问题得到了这段代码，但是节点抱怨使用process.stdin.setRawMode而不是tty，所以我更改了它.

I got this code from a different SO question, but node complained to use process.stdin.setRawMode instead of tty, so I changed it.

之前:

var tty = require("tty");

process.openStdin().on("keypress", function(chunk, key) {
  if(key && key.name === "c" && key.ctrl) {
    console.log("bye bye");
    process.exit();
  }
});

tty.setRawMode(true);

之后:

process.stdin.setRawMode(true);
process.stdin.on("keypress", function(chunk, key) {
  if(key && key.name === "c" && key.ctrl) {
    console.log("bye bye");
    process.exit();
  }
});

无论如何，它只是创建一个完全不响应的节点进程，什么也不做，第一个抱怨tty，然后抛出一个错误，第二个什么都不做，并禁用Node的本机 CTRL + C 处理程序，因此当我按它时它甚至都不会退出节点.如何在 Windows 中成功处理 Ctrl + C ?

In any case, it's just creating a totally nonresponsive node process that does nothing, with the first complaining about tty, then throwing an error, and the second just doing nothing and disabling Node's native CTRL+C handler, so it doesn't even quit node when I press it. How can I successfully handle Ctrl+C in Windows?

推荐答案

如果要捕获中断信号SIGINT，则无需从键盘读取. nodejs的process对象公开了一个中断事件:

If you're trying to catch the interrupt signal SIGINT, you don't need to read from the keyboard. The process object of nodejs exposes an interrupt event:

process.on('SIGINT', function() {
    console.log("Caught interrupt signal");

    if (i_should_exit)
        process.exit();
});

编辑:如果没有解决方法，则无法在Windows上使用. 在此处查看

Edit: doesn't work on Windows without a workaround. See here

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