在numpy向量中找到最频繁的数字 [英] Find the most frequent number in a numpy vector

问题描述

假设我在python中有以下列表:

Suppose I have the following list in python:

a = [1,2,3,1,2,1,1,1,3,2,2,1]

如何以一种简洁的方式在此列表中找到最频繁的电话号码?

How to find the most frequent number in this list in a neat way?

推荐答案

如果您的列表包含所有非负整数，则应查看numpy.bincounts:

If your list contains all non-negative ints, you should take a look at numpy.bincounts:

http://docs.scipy.org/doc/numpy/reference/produced /numpy.bincount.html

然后可能使用np.argmax:

and then probably use np.argmax:

a = np.array([1,2,3,1,2,1,1,1,3,2,2,1])
counts = np.bincount(a)
print np.argmax(counts)

对于更复杂的列表(可能包含负数或非整数值)，可以类似的方式使用np.histogram.另外，如果您只想在python中工作而不使用numpy，则collections.Counter是处理此类数据的好方法.

For a more complicated list (that perhaps contains negative numbers or non-integer values), you can use np.histogram in a similar way. Alternatively, if you just want to work in python without using numpy, collections.Counter is a good way of handling this sort of data.

from collections import Counter
a = [1,2,3,1,2,1,1,1,3,2,2,1]
b = Counter(a)
print b.most_common(1)

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