执行元组算术的优雅方法 [英] Elegant way to perform tuple arithmetic

问题描述

在Python 2.7中执行元组算术的最优雅，简洁的方法是什么(无需使用操作符重载创建我自己的类)?

What is the most elegant and concise way (without creating my own class with operator overloading) to perform tuple arithmetic in Python 2.7?

让我们说我有两个元组:

Lets say I have two tuples:

a = (10, 10)
b = (4, 4)

我的预期结果是

c = a - b = (6, 6)

我当前正在使用:

c = (a[0] - b[0], a[1] - b[1])

我也尝试过:

c = tuple([(i - j) for i in a for j in b])

，但结果为(6, 6, 6, 6).我相信以上内容可作为嵌套的for循环，在结果中产生4次迭代和4个值.

but the result was (6, 6, 6, 6). I believe the above works as a nested for loops resulting in 4 iterations and 4 values in the result.

推荐答案

如果要快速查找，可以使用numpy:

If you're looking for fast, you can use numpy:

>>> import numpy
>>> numpy.subtract((10, 10), (4, 4))
array([6, 6])

，如果您想将其保存在一个元组中:

and if you want to keep it in a tuple:

>>> tuple(numpy.subtract((10, 10), (4, 4)))
(6, 6)

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