将numpy数组转换为元组 [英] Convert numpy array to tuple

问题描述

注意:这是与通常的元组到数组的转换相反的要求.

Note: This is asking for the reverse of the usual tuple-to-array conversion.

我必须将参数传递给(包装的c ++)函数作为嵌套元组.例如，以下作品

I have to pass an argument to a (wrapped c++) function as a nested tuple. For example, the following works

X = MyFunction( ((2,2),(2,-2)) )

而以下不

X = MyFunction( numpy.array(((2,2),(2,-2))) )
X = MyFunction( [[2,2],[2,-2]] )

不幸的是，我想使用的参数以numpy数组的形式出现.对于某些N，该阵列的尺寸始终为2xN，这可能会很大.

Unfortunately, the argument I would like to use comes to me as a numpy array. That array always has dimensions 2xN for some N, which may be quite large.

是否有一种简单的方法可以将其转换为元组?我知道我可以循环遍历，创建一个新的元组，但是如果numpy数组提供了一些不错的访问方式，则希望使用它.

Is there an easy way to convert that to a tuple? I know that I could just loop through, creating a new tuple, but would prefer if there's some nice access the numpy array provides.

如果不可能如我所愿地做到这一点，那么通过循环执行此操作的最漂亮的方法是什么?

If it's not possible to do this as nicely as I hope, what's the prettiest way to do it by looping, or whatever?

推荐答案

>>> arr = numpy.array(((2,2),(2,-2)))
>>> tuple(map(tuple, arr))
((2, 2), (2, -2))

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