如何使用另一个数组的值过滤一个numpy数组? [英] How to filter a numpy array using another array's values?

问题描述

我有两个NumPy数组，例如:

I have two NumPy arrays, e.g.:

a = [1,2,3,4,5]

和一个过滤器数组，例如:

and a filter array, e.g.:

f = [False, True, False, False, True]

len(a) == len(f)

如何获取仅具有f中相同索引为True的值的新numpy数组?就我而言:[2, 5].

How can I get a new numpy array with only the values in a where the same index in f is True? In my case: [2, 5].

根据接受的解决方案(具有不同的值):

According to the accepted solution (with different values):

>>> a = numpy.array([ 1,  2,  3,  4,  5,  6,  7,  8,  9, 10])
>>> b = numpy.array([True, False, True, False, True, False, True, False, True, False])
>>> a[b]
array([1, 3, 5, 7, 9])

推荐答案

NumPy支持这假定a和f是NumPy数组而不是Python列表(如问题所示).您可以使用f = np.array(f)进行转换.

This assumes that a and f are NumPy arrays rather than Python lists (as in the question). You can convert with f = np.array(f).

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